All categories

2 years ago

Write an algebraic expression for the verbal expression, "17 less than k and 12"

Mathematics

1 answer:

Sonbull [250]2 years ago

4 0

Answer:

k-5

Step-by-step explanation:

"k and 12" : (k + 12)

"17 less than k and 12" : (k + 12) - 17

simplifying:

(k + 12) - 17

= k + 12 - 17

= k-5

You might be interested in

What is the standard form for 200,000+80,000+700+6

ozzi

280,706 is the standard form

7 0

2 years ago

PLEASE HELP!!!! URGENT. 20 POINTS AND ILL GIVE YOU BRAINLIEST!!

Leokris [45]

Answer:

magma blocks

Step-by-step explanation:

by using your die you can eat as many magma blocks as you want, keep in mind. your goal is to get to dragon level. they eat the fastest! you need to consume atleast 5 magma blocks to reach level dragon. (i hope this can help you)

3 0

2 years ago

A car starts from an initial velocity of 10m/s and accelerates at 2.5m/s².how long will it take the car to reach a speed of 40m/

PIT_PIT [208]

A=(v-u)/t
We know a=2.5, v=40, u=10, so:
2.5=(40-10)/t
2.5t=40-10
2.5t=30
Divide both sides by 2.5
t=12 It takes 12 seconds for the car to reach 40m/s

To find out how far it went, you do:
d=v+1/2 at^2
d=10+1/2(2.5)(12)^2
d=10+1/2(2.5)(144)
d=10+(1.25)(72)
d=10+90
d=100m

Hope this helps :)

7 0

2 years ago

Please help easy time table consumer math <3

BabaBlast [244]

22 hours long he works

7 0

3 years ago

A new phone system was installed last year to help reduce the expense of personal calls that were being made by employees. Befor

Leya [2.2K]

Using the normal distribution, it is found that there was a 0.9579 = 95.79% probability of a month having a PCE between $575 and $790.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

$\mu = 700, \sigma = 50$ .

The probability of a month having a PCE between $575 and $790 is the <u>p-value of Z when X = 790 subtracted by the p-value of Z when X = 575</u>, hence:

X = 790:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{790 - 700}{50}$

Z = 1.8

Z = 1.8 has a p-value of 0.9641.

X = 575:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{575 - 700}{50}$

Z = -2.5

Z = -2.5 has a p-value of 0.0062.

0.9641 - 0.0062 = 0.9579.

0.9579 = 95.79% probability of a month having a PCE between $575 and $790.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

3 0

1 year ago