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saw5 [17]
3 years ago
8

Julie drove a motorcycle in a race. She averaged 35 mph and began the race 0.25 hours ahead of the other drivers. The variable d

represents Julie's distance driven, in miles. The variable t represents the number of hours since the other drivers began to race.
Which equation can be used to determine the distance Julie drove t hours into the race?


d=35t−0.25

d = 35t + 0.25

d=35(t+0.25)

d=35(t−0.25)
Mathematics
1 answer:
alina1380 [7]3 years ago
3 0

You would need to add 0.25 from t to get the number of hours ( this would be the total number of hours she has raced) and then multiply that by her speed.

The equation would be d = 35(t+0.25)

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Find the coordinates of the turning point for the equation of the graph below y=x^2+14x+45
USPshnik [31]

Answer:

(- 7, - 4 )

Step-by-step explanation:

Given a quadratic in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the turning point is

x = - \frac{b}{2a}

y = x² + 14x + 45 ← is in standard form

with a = 1, b = 14 , then

x = - \frac{14}{2} = - 7

Substitute x = - 7 into the equation and evaluate for y

y = (- 7)² + 14(- 7) + 45 = 49 - 98 + 45 = - 4

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4 0
2 years ago
Big chickens: The weights of broilers (commercially raised chickens) are approximately normally distributed with mean 1387 grams
Nataliya [291]

Answer:

a) 0.2318

b) 0.2609

c) No it is not unusual for a broiler to weigh more than 1610 grams

Step-by-step explanation:

We solve using z score formula

z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

Mean 1387 grams and standard deviation 192 grams. Use the TI-84 Plus calculator to answer the following.

(a) What proportion of broilers weigh between 1150 and 1308 grams?

For 1150 grams

z = 1150 - 1387/192

= -1.23438

Probability value from Z-Table:

P(x = 1150) = 0.10853

For 1308 grams

z = 1308 - 1387/192

= -0.41146

Probability value from Z-Table:

P(x = 1308) = 0.34037

Proportion of broilers weigh between 1150 and 1308 grams is:

P(x = 1308) - P(x = 1150)

0.34037 - 0.10853

= 0.23184

≈ 0.2318

(b) What is the probability that a randomly selected broiler weighs more than 1510 grams?

1510 - 1387/192

= 0.64063

Probabilty value from Z-Table:

P(x<1510) = 0.73912

P(x>1510) = 1 - P(x<1510) = 0.26088

≈ 0.2609

(c) Is it unusual for a broiler to weigh more than 1610 grams?

1610- 1387/192

= 1.16146

Probability value from Z-Table:

P(x<1610) = 0.87727

P(x>1610) = 1 - P(x<1610) = 0.12273

≈ 0.1227

No it is not unusual for a broiler to weigh more than 1610 grams

8 0
3 years ago
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