Answer:
She should offer a guarantee of 13.76 years.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
The average life of a certain type of small motor is 10 years with a standard deviation of 2 years.
This means that 
If she is willing to replace 3% of the motors that fail, how long a guarantee (in years) should she offer?
She should offer the 100 - 3 = 97th percentile as a guarantee, so X when Z has a pvalue of 0.97, that is, X when Z = 1.88.
She should offer a guarantee of 13.76 years.
3x+3-x+(-7)>6
combine like terms on left side
2x-4>6
add 4 to both sides 2x>10
x=10/2 = 5
x>5
No 9.717 is greater than 9.707 because 9.717 would be seven hundred seven thousandths and 9.717 would be seven hundred seven teen hundredths.
We have that
smaller figure
ha=8.7
ra=1.6
larger figure
hb=10.44
rb=1.92
ha/hb=8.7/10.44----> 0.83
ra/rb=1.6/1.92-------> 0.83
ratio smaller figure to the larger figure
1.6/1.92-------> divided by 1.6 both members
[1.6/1.6]/[1.92/1.6]-------> 1/1.2
the ratio ha/hb is equal to the ratio ra/rb
so
the smaller figure and the larger figure are similar
and the ratio smaller figure to the larger figure is equal to----> 1/1.2
the answer is
the option
yes 1/1.2
9514 1404 393
Answer:
a. 0.81
b. v = 28000(0.81^n)
c. 2757.36
Step-by-step explanation:
a. The growth factor is 1 more than the growth rate. Here, the growth rate is -19% (per year), so the growth factor, the multiplier, is ...
1 -0.19 = 0.81
__
b. The equation sets value equal to the original value multiplied by the growth factor to the power of the number of years:
value = (original value) × (growth factor)^n
v = 28000(0.81^n)
__
c. For n=11, this is ...
v = 28000(0.81^11) ≈ 2757.36
The value of the truck after 11 years is about $2757.
