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AlekseyPX
4 years ago
15

99 Points.

Mathematics
2 answers:
kvasek [131]4 years ago
6 0

The product of the sum of two perfect cubes:

a³ + b³ = (a + b)(a² - ab + b²)

The product of the difference of two perfect cubes:

a³ - b³ = (a - b)(a² + ab + b²)

----------------------------------------------------------------------------------------------------------------

Remember to follow FOIL:

(b^2 + 8)(b^2 - 8)

(b^2)(b^2) = b^4

(b^2)(-8) = -8b^2

(8)(b^2) = 8b^2

(8)(-8) = -64

b^4 - 8b^2 + 8b^2 - 64

Combine like terms:

b^4 (-8b^2 + 8b^2) - 64

b^4 - 64

b^4 - 64 is your answer

hope this helps

8_murik_8 [283]4 years ago
6 0

The product of the sum of two perfect cubes:

a³ + b³ = (a + b)(a² - ab + b²)

The product of the difference of two perfect cubes:

a³ - b³ = (a - b)(a² + ab + b²)

----------------------------------------------------------------------------------------------------------------

Remember to follow FOIL:

(b^2 + 8)(b^2 - 8)

(b^2)(b^2) = b^4

(b^2)(-8) = -8b^2

(8)(b^2) = 8b^2

(8)(-8) = -64

b^4 - 8b^2 + 8b^2 - 64

Combine like terms:

b^4 (-8b^2 + 8b^2) - 64

b^4 - 64

b^4 - 64 is your answer

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Step-by-step explanation:

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The Coefficient of determination (R²) :

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R² = 0.8676328

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Andrews [41]

Answer:

Step-by-step explanation:

-2x² + 12x  + 32 = 0

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positive discriminant means there are two distinct real roots

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8 0
3 years ago
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antoniya [11.8K]

Answer:

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Step-by-step explanation:

We can use the leg rule

hyp          leg

------- =  -----------------

leg            part

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------- =  -----------------

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Using cross products

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