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3 years ago

F(x) = 2x + 7;translation 4 right Write a function

Mathematics

1 answer:

katrin2010 [14]3 years ago

5 0

Answer:

G(x) = 2(x-4) +7

Step-by-step explanation:

When it is a translation 4 units to the right you put (x-4) because the parent function is f(x) = a(x-h) +k

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Stuck on this math question

Bess [88]

Answer:

SinA = √5/3

CosB = √5/3

Step-by-step explanation:

First let us find the value of a. This is illustrated below:

a^2 = 6^2 — 4^2

a^2 = 36 — 16

a^2 = 20

Take the square root of both side

a = √20 = √(4 x 5) = √4 x √5

a = 2√5

From the diagram,

For sinA

Opp = 2√5

Hypo = 6

Adj = 4

SinA = opp /Hypo

SinA = 2√5/6

SinA = √5/3

For CosB

Opp = 4

Hypo = 6

Adj = 2√5

CosB = Adj /Hypo

CosB = 2√5/6

CosB = √5/3

4 0

3 years ago

Determine the coordinates of the vertex for each quadratic function and whether the parabola has a maximum or minimum. 4. y = x²

GREYUIT [131]

Answer:

minimum, coordinates of vertex: (-3,-11)

explanation:

$\sf y =x^2 +6x-2$

x coordinates on vertex:

<u>solving steps</u>:

$\sf \dfrac{-b}{2a}$

$\sf \dfrac{-6}{2(1)}$

$\sf -3$

<u>Find y-coordinate on vertex:</u>

$\sf y =x^2 +6x-2$

$\sf y =(-3)^2 +6(-3)-2$

$\sf y =-11$

$\mathrm{If}\:a < 0,\:\mathrm{then\:the\:vertex\:is\:a\:maximum\:value}$

$\mathrm{If}\:a > 0,\:\mathrm{then\:the\:vertex\:is\:a\:minimum\:value}$

coordinates: (-3,-11) thus minimum

6 0

3 years ago

Read 2 more answers

Can someone help please

muminat

Answer:

sorry i dont know

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Multiply. 6 1/4 x 3 3/5 =

Shalnov [3]

45/2 or 22 1/2
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6 0

3 years ago

A model rocket launched directly upward at a speed of 16 meters per second from a helght of 2 meters . The f(t) = - 4.9t ^ 2 + 1

Anton [14]

Answer:

f(t) = 15.06 m

Step-by-step explanation:

The relationship between the height of the rocket and the time after launch, t. In seconds is given by :

$f(t) = - 4.9t ^ 2 + 16t + 2$

We need to find the maximum height the rocket will reach the ground.

When it reaches the ground,

f(t) = 0

So,

Maximum height,

f'(t) = 0

$-9.8t+16=0\\\\t=\dfrac{16}{9.8}\\\\t=1.63\ s$

Put t = 1.63 in equation (1).

$f(1.63) = - 4.9\times (1.63 ^ 2) + 16(1.63) + 2\\\\=15.06\ m$

So, the maximum height of the rocket is 15.06 m.

4 0

3 years ago