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4 years ago

Do not multiply by pi. Just use the whole number and do not try to include pi in the

Mathematics

1 answer:

IrinaK [193]4 years ago

4 0

Answer:

Surface area = 1808.64in² and volume is 7234.56in³

Step-by-step explanation:

The figure above is a sphere, and it has a diameter of 24in

Radius = ?

Radius = diameter / 2

R = 24 / 2

R = 12in

Surface area of of sphere = 4πr²

Volume of a sphere = 4/3 πr³

π = 3.14

1. Surface area = 4 * 3.14 * 12²

Surface area = 4 * 3.14 * 144

Surface area = 1808.64in²

2. Volume of the sphere = 4/3πr³

Volume = 4/3 * 3.14 * 12³

Volume = 4/3 * 3.14 * 1728

Volume = 7234.56in³

The surface area of the sphere is 1808.64in² and the volume is 7234

56in³

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The coordinates of A, B, and C in the diagram are A(p,4), B(6,1), and C(9,q). Which equation correctly relates p and q?

siniylev [52]

Answer:

$q+p=7$

Step-by-step explanation:

we know that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

In this problem line AB and line BC are perpendicular

$m_A_B*m_B_C=-1$

step 1

Find the slope AB

we have

A(p,4), B(6,1)

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the values

$m=\frac{1-4}{6-p}$

$m_A_B=-\frac{3}{6-p}$

step 2

Find the slope BC

we have

B(6,1), and C(9,q)

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the values

$m=\frac{q-1}{9-6}$

$m_B_C=\frac{q-1}{3}$

step 3

Find the equation that relates p and q

we know that

$m_A_B*m_B_C=-1$

we have

$m_A_B=-\frac{3}{6-p}$

$m_B_C=\frac{q-1}{3}$

substitute

$(-\frac{3}{6-p})(\frac{q-1}{3})=-1$

$(\frac{q-1}{6-p})=1$

$q-1=6-p\\q+p=7$

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3 years ago

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hram777 [196]

Answer:

x = $\frac{y-b}{m}$

Step-by-step explanation:

Given

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4 years ago

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Answer:

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3 years ago

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3 years ago

What is the area of the square?

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4 years ago

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