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4 years ago

I am having some trouble with finding out the two problems for this question, can you please help me?

Mathematics

1 answer:

sattari [20]4 years ago

4 0

What is it telling us to do- and what do we know?

To find the perimeter of the problem, add all side lengths together.

To find the area, add all the areas of the piece together.

Imagine your taking the piece apart.

Find the area of each separate piece.

to find the width of c and d, divide 70 by 14. That = 5

There are five separate widths-b- c- d and all in between, so we can safely assume each width is 14.

To find the area of b, multiply 50-12 by 14. 38*14=542

To find the area of c, multiply 25 by 14=350

To find the area of d, multiply 50 by 14, because at the top we can see its equal to 50. That =700

Then finally, to find the area of a, multiply 70 by 12 to get 840. Added all together, the total area is 2432.

To find the perimeter, we take all the data we've gathered about the side lengths and add it together. The total perimeter is 414.

Hope this helps!

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Sandwiches at the deli cost $4.75 each and drinks cost $0.95 each. mrs. singh has $30.00 to spend. will $30.00 be enough to buy

frosja888 [35]

Yes he will because 4.75 x 5 = 23.75 plus 0.95 x 5 = 28.5

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3 years ago

If the range of the coordinate transformation f(x,y) = (x – 5, y – 3) is (-6,-6) and (2,-3).

lina2011 [118]

Answer:

(-2,1),(-1,2),(-3,5/3)

Step-by-step explanation:

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3 years ago

What is the greatest common factor of 8m, 36m", and 12?

wlad13 [49]

Answer: 4

Step-by-step explanation:

8m = 2*2*2*m

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3 years ago

Use the given equation to complete the table:

Ne4ueva [31]

Answer:

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5 0

3 years ago

Hi boys can you help me pls!!!!!!!

goblinko [34]

Answer: OPTION A.

Step-by-step explanation:

Given the following function:

$h(x)=-\frac{1}{4}x^2+\frac{1}{2}x+\frac{1}{2}$

You know that it represents the the height of the ball (in meters) when it is a distance "x" meters away from Rowan.

Since it is a Quadratic function its graph is parabola.

So, the maximum point of the graph modeling the height of the ball is the Vertex of the parabola.

You can find the x-coordinate of the Vertex with this formula:

$x=\frac{-b}{2a}$

In this case:

$a=-\frac{1}{4}\\\\b=\frac{1}{2}$

Then, substituting values, you get:

$x=\frac{-\frac{1}{2}}{(2)(-\frac{1}{4}))}\\\\x=1$

Finally, substitute the value of "x" into the function in order to get the y-coordinate of the Vertex:

$h(1)=y=-\frac{1}{4}(1)^2+\frac{1}{2}(1)+\frac{1}{2}\\\\y=0.75$

Therefore, you can conclude that:

<em> The maximum height of the ball is 0.75 of a meter, which occurs when it is approximately 1 meter away from Rowan.</em>

7 0

3 years ago