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3 years ago

I am having some trouble with finding out the two problems for this question, can you please help me?

Mathematics

1 answer:

sattari [20]3 years ago

4 0

What is it telling us to do- and what do we know?

To find the perimeter of the problem, add all side lengths together.

To find the area, add all the areas of the piece together.

Imagine your taking the piece apart.

Find the area of each separate piece.

to find the width of c and d, divide 70 by 14. That = 5

There are five separate widths-b- c- d and all in between, so we can safely assume each width is 14.

To find the area of b, multiply 50-12 by 14. 38*14=542

To find the area of c, multiply 25 by 14=350

To find the area of d, multiply 50 by 14, because at the top we can see its equal to 50. That =700

Then finally, to find the area of a, multiply 70 by 12 to get 840. Added all together, the total area is 2432.

To find the perimeter, we take all the data we've gathered about the side lengths and add it together. The total perimeter is 414.

Hope this helps!

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Find the length of the missing side. triangle with an 8 inch side and 12 inch side with a right angle 8.9 in. 104 in. 4 in 14.4

Mamont248 [21]

Given:

In a triangle, length of one side is 8 inches and length of another side is 12 inches, and an angle is a right angle.

To find:

The length of the missing side.

Solution:

In a right angle triangle,

$Hypotenuse^2=Perpendicular^2+Base^2$

Suppose the measures of sides adjacent to the right angle are 8 inches and 12 inches.

Substituting Perpendicular = 8 inches and Base = 12 inches, we get

$Hypotenuse^2=8^2+12^2$

$Hypotenuse^2=64+144$

$Hypotenuse^2=208$

Taking square root on both sides, we get

$Hypotenuse=\sqrt{208}$

$Hypotenuse=14.422205$

$Hypotenuse\approx 14.4$

The length of the missing side is 14.4 inches. Therefore, the correct option is D.

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