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Helga [31]
3 years ago
14

Lonnie threw 50 free throws and missed 16 of them. If Lonnie throws 75 free throws, what can be predicted about the number she w

ill make successfully?
A. Lonnie will make 24 free throws.
B. Lonnie will make 51 free throws.
C. Lonnie will make 59 free throws.
D. Lonnie will make 66 free throws.
Mathematics
2 answers:
qaws [65]3 years ago
8 0

Answer:

B. Lonnie will make 59 free throws

zalisa [80]3 years ago
6 0

Answer:

B. Lonnie will make 59 free throws

Step-by-step explanation:

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Xy to the 7th power divided by x to the 3rd power y to the 4th power
bearhunter [10]

Answer:

y to the 6 over x to the 2

Step-by-step explanation:

4 0
3 years ago
2x+14y=-108 9x+2y= 2 Solve the following system of equations using any method
Orlov [11]
<span>2x+14y=-108
</span><span>63x+14y= 14       (multiply the second equation by 7 and subtract)
_____________
-61x=-122
x=-122/-61
x=2
2(2)+14y=-108
4+14y=-108
14y=-112
y=-112/14
y=-8

</span>
4 0
3 years ago
Divide and simplify 5/12÷20/36
gregori [183]
Hello there! The formula for dividing fraction is keep, change, flip. You keep the first fraction the same, change division into multiplication, and flip the second fraction over by its reciprocal. In this case, 5/12 remains the same, division becoems multiplication, and 20/36 flips over to become 36/20. So the expression becomes this:

5/12 * 36/20

Now, we multiply straight across. 5 * 36 is 180. 12 * 20 is 240. 180/240 is 3/4 in simplest form. There. The quotient is 3/4.
3 0
3 years ago
Which of the following statements shows a characteristic of a statistical question? (4 points)
cestrela7 [59]
The answer is D I hope that helped
5 0
3 years ago
Read 2 more answers
Can someone please help me?
kvasek [131]

now, let's recall the rational root test, check your textbook on it.

so p  = 18 and q = 1

so all possible roots will come from the factors of ±p/q

now, to make it a bit short, the factors are loosely, ±3, ±2, ±9, ±1, ±6.

recall that, a root will give us a remainder of 0.

let us use +3.


\bf x^4-7x^3+13x^2+3x-18 \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{r|rrrrr} 3&1&-7&13&3&18\\ &&3&-12&3&18\\ \cline{1-6} &1&-4&1&6&0 \end{array}\qquad \implies (x-3)(x^3-4x^2+x+6)


well, that one worked... now, using the rational root test, our p = 6, q = 1.

so the factors from ±p/q are ±3, ±2, ±1

let's use 3 again


\bf \begin{array}{r|rrrrr} 3&1&4&1&6\\ &&3&-3&-6\\ \cline{1-5} &1&-1&-2&0 \end{array}\qquad \implies (x-3)(x-3)(x^2-x-2)


and of course, we can factor x²-x-2 to (x-2)(x+1).

(x-3)(x-3)(x-2)(x+1).

7 0
3 years ago
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