12 bags = $27
multiply both sides by 6,
72 bags = $27*6 = $162
Answer:
0.952
Step-by-step explanation:
we know that
here standard error =std deviation÷(n)^1/2
=15/(25)^1/2 =15/5=3
Assuming that IQ scores are normally distributed
Now, probability of a Type II error
=P(X<110) = P(Z<(110-105)/3)=P(Z<1.67)
=0.952
the power of the test if the true population mean is 105 = 0.952
In the second sample 6/40 had tags.
Assuming it represents the whole population then 58/total population = 6/40
6 x total = 58 x 40
total population = 58 x 40 / 6 = 387 so around 400
