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3 years ago

What is the age of Alps mountain

Mathematics

2 answers:

DIA [1.3K]3 years ago

5 0

Step-by-step explanation:

The Alps were born 770 million years ago.

Hope this helps..

devlian [24]3 years ago

3 0

Answer: About 65 million years ago.

Step-by-step explanation: The Alps emerged during the alpine orogeny, an event that began about 65 million years ago as the Mesozoic era was drawing to a close.

PLEASE MARK ME AS BRAINLIEST IF MY ANSWER IS RIGHT.

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A video game system and several games are sold for $700. The cost of the games is three times as much as cost of the system. Fin

soldier1979 [14.2K]

Answer:

cost of system is $175 and cost of the games is $525

Step-by-step explanation:

Let us take the cost of the system to be X.The games cost 3 times as much as the system and are therefore given 3X. The total cost of the system and the games is $700.Therefore,we form the equation 3X+X=$700.Meaning that 4X=$700 and X is equal to $175.The cost of the system is X therefore it is $175 and the cost of the games is 3X and is therefore $525.

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3 years ago

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3 years ago

PLEASE HELP ME GUYS OR I WONT PASS this calculus!!!!

KonstantinChe [14]

Answer:

b. $\displaystyle \frac{1}{2}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Functions
Function Notation
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$
Exponential Rule [Root Rewrite]: $\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}$

Calculus

Derivatives

Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle H(x) = \sqrt[3]{F(x)}$

Step 2: Differentiate

Rewrite function [Exponential Rule - Root Rewrite]: $\displaystyle H(x) = [F(x)]^\bigg{\frac{1}{3}}$
Chain Rule: $\displaystyle H'(x) = \frac{d}{dx} \bigg[ [F(x)]^\bigg{\frac{1}{3}} \bigg] \cdot \frac{d}{dx}[F(x)]$
Basic Power Rule: $\displaystyle H'(x) = \frac{1}{3}[F(x)]^\bigg{\frac{1}{3} - 1} \cdot F'(x)$
Simplify: $\displaystyle H'(x) = \frac{F'(x)}{3}[F(x)]^\bigg{\frac{-2}{3}}$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle H'(x) = \frac{F'(x)}{3[F(x)]^\bigg{\frac{2}{3}}}$

Step 3: Evaluate

Substitute in x [Derivative]: $\displaystyle H'(5) = \frac{F'(5)}{3[F(5)]^\bigg{\frac{2}{3}}}$
Substitute in function values: $\displaystyle H'(5) = \frac{6}{3(8)^\bigg{\frac{2}{3}}}$
Exponents: $\displaystyle H'(5) = \frac{6}{3(4)}$
Multiply: $\displaystyle H'(5) = \frac{6}{12}$
Simplify: $\displaystyle H'(5) = \frac{1}{2}$