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3 years ago

PLSS I NEED HELP I NEED HELP SOMEONE SAVE ME

Mathematics

1 answer:

S_A_V [24]3 years ago

8 0

Answer:

sorry but are you dyin why do u need help why do you need someone to save you just say i need answers to this equation pls

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Use the distributive property to write an expression that is equivalent to each expression 1/5(20y - 4x - 13)

DiKsa [7]

The answer should be
4y-4/5x-13/5

8 0

3 years ago

Question 4 (1 point) Determine whether the ordered pair (3,28) is a solution to the equation 2x- y/2 = -8 (3, 28) Is a solution

bulgar [2K]

Answer:

It is a solution

Step-by-step explanation:

Given

$2x - \frac{y}{2} = -8$

Required

Determine if $(3,28)$ is a solution

$(3,28)$ implies that:

$x = 3$

$y = 28$

To check if it is a solution, we simply substitute values for x and y in the given equation;

$2x - \frac{y}{2} = -8$

$2(3) - \frac{28}{2} = -8$

$6 - 14= -8$

$-8= -8$

Since both sides of the equation are equal; then, Yes, it is a solution

6 0

2 years ago

What is the remainder when 3 is synthetically divided into the polynomial -2x^2 + 7x - 9?

goblinko [34]

Answer:

for apex the answer is -6

Step-by-step explanation:

6 0

3 years ago

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Work out the angle of elevation from the

insens350 [35]

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \:Angle \:\: of \:\: elevation= 30°$

____________________________________

$\large \tt Solution \: :$

Let the angle of elevation be " x "

$\qquad \tt \rightarrow \: \cos(x) = \dfrac{9 \sqrt{3} }{18}$

$\qquad \tt \rightarrow \: \cos(x) = \dfrac{ \sqrt{3} }{2}$

$\qquad \tt \rightarrow \: x = \cos {}^{ - 1} \bigg( \cfrac{ \sqrt{3} }{2} \bigg )$

$\qquad \tt \rightarrow \: x = 30 \degree \: \: or \: \: \cfrac{ \pi}{6} \: \: rad$

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

8 0

2 years ago

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Using the quadratic formula to solve 4x2 – 3x + 9 = 2x + 1, what are the values of x?

yaroslaw [1]

Answer:

The value of x is:

$x=\dfrac{5\pm \sqrt{103}i}{8}$

Step-by-step explanation:

we have to use the quadratic formula to solve for x.

The equation is given as:

$4x^2-3x+9=2x+1$

which could also be written as:

$4x^2-3x+9-2x-1=0\\\\4x^2-3x-2x+9-1=0\\\\\\4x^2-5x+8=0$

The quadratic formula for the quadratic equation of the type:

$ax^2+bx+c=0$ is given as:

$x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

Here we have:

a=4, b=-5 and c=8.

Hence, by the quadratic formula we have:

$x=\dfrac{-(-5)\pm \sqrt{(-5)^2-4\times 8\times 4}}{2\times 4}\\\\x=\dfrac{5\pm \sqrt{25-128}}{8}\\\\\\x=\dfrac{5\pm \sqrt{103}i}{8}$

Hence, the value of x is:

$x=\dfrac{5\pm \sqrt{103}i}{8}$

8 0

3 years ago

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