Answer:
Rounding is selected to match the precision required. Rounding to the nearest hundredth provides better precision than rounding to the nearest tenth.
Explanation.
Suppose you calculate the value of a variable x as $300.0143.
Because $0.143 or 14.3 cents is not available, we round 14.3 cents to 14 cents, and x = $300.14.
In this case, we have rounded to the nearest hundredth.
If you do not want to be bothered with pennies, you ignore the four pennies and round 14 cents to 10 cents, and x = $300.10.
In this case, we have rounded to the nearest tenth.
The total mass was 149.5 grams.
Setting up an equation, we have that the sample size, 39.1, is 5 3/4 (5.75) grams less than 3/10 of the total mass; this gives us
39.1 = 3/10x - 5.75
Adding 5.75 to both sides, we have
44.85 = 3/10x
Multiplying both sides by 10,
448.5 = 3x
Dividing both sides by 3,
149.5 = x
The recursive sequence that would produce the sequence 8,-35,137,… is T(n + 1) = -3 - 4T(n) where T(1) = 8
<h3>How to determine the recursive sequence that would produce the sequence?</h3>
The sequence is given as:
8,-35,137,…
From the above sequence, we can see that:
The next term is the product of the current term and -4 added to -3
i.e.
Next term = -3 + Current term * -4
So, we have:
T(n + 1) = -3 + T(n) * -4
Rewrite as:
T(n + 1) = -3 - 4T(n)
Hence, the recursive sequence that would produce the sequence 8,-35,137,… is T(n + 1) = -3 - 4T(n) where T(1) = 8
Read more about recursive sequence at
brainly.com/question/1275192
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hip hop and randb y u deleted my answering was I being bias?
Answer: 10 m^2.
Explanation:
A = 1/2 (a)(b)
A = 1/2 (4m)(5m)
A = 1/2 (20m^2) = 10 m2.