Answer:
A.
Step-by-step explanation:
Corral is circular in shape.
Radius of the corral would be be the distance from the post to the edge of the corral.
-> r = 8 ft

Answer:
(g-f) (-1)= sqrt(15)
(f/g)(-1)= 0
(g+f)(2)=sqrt(3)-3
(g*f)(2)=-3*sqrt(3)
Step-by-step explanation:
We have to eval the expressions given in the point indicated.
Lets start by the first equation
(g-f)(-1)= g(-1) - f(-1)=
= 
Now, lest continue with the others
(f/g)(-1)= f(-1)/g(-1)= (1-1)/sqrt(15)=0
(g+f)(2)=g(2)+f(2)=sqrt(3)-3
(g*f)(2)=g(2)*f(2)=sqrt(3)*(-3)=-3sqrt(3)
Answer:
4.6 hours
Step-by-step explanation:
we first need to calculate the total distance he covered and total time taken whole for the journey.
Distance= speed X time
time = Distance/speed
let the total distance be X. he covers 2/5 if the journey first.
2/5 = 0.4
Time = 0.4x/45 hours
the remaining journey is 3/5x
he covers 1/3 X 3/5= 0.2x
time taken = 0.2/90 X hours
the remaining distance = 100× 1.2 = 120km
we add 0.4x + 0.2x to get the fraction he had covered
0.6x.
the remaining distance was X - 0.6x = 0.4 X
thus 120 km represents 0.4x of the journey
we calculate now the value of X
0.4x = 120
X = 300km
Total time taken = 0.4x/45 + 0.2/90 + 1.2 hours
replace X to get time
2.7 hours + 0.7 hours + 1.2 hours
= 4.6 hours
Answer:
0.8 cm
Step-by-step explanation:
The formula for MAD is attached in the picture.
x_i are the values (data)
x bar is the mean
n is the number of numbers (data)
For figuring out MAD, basically, <em>we subtract the mean from each of the values respectively and take the absolute value and SUM for all of the numbers in the data set. Then we divide by n, the number of numbers.</em>
<em />
Let's do this:
MAD = 
MAD is 0.8
The answer is: "
270 minutes " .
__________________________________________________________ → There are "
270 minutes" in "4 hours and 30 minutes" .
__________________________________________________________Explanation:__________________________________________________________Method 1):__________________________________________________________ Note: 60 minutes = 1 hour (exactly);
30 minutes =
? hr ? ;
→ (30 minutes) * (1 hr/ 60 minutes) ;
= (30/60) hr
= (3/6) hr
= (3÷3)/(6÷3) hr ;
= "
hr " ;
or; write as: "
0.5 hr " .
_________________________________________________________So "4 hours & 30 minutes" = 4 hours + 0.5 hours = 4.5 hours.
→ 4.5 hours
= ? minutes ;
The answer is: " 270 minutes" . 4.5 hours *

;
= (4.5 * 60) minutes
= "
270 minutes " .
→ The answer is: "
270 minutes ".
___________________________________________________________
Method 2) ___________________________________________________________ "4 hours and 30 minutes" =
<u> ? </u> minutes " .
___________________________________________________________→ " 4 hours
= <u> ? </u> minutes " ;
→ 4 hr . *
= (4 * 60) minutes
= 240 min. ;
→ There are " 240 minutes in 4 hours" .
→ To find the number of "minutes" in "4 hours and 30 minutes" ;
→ we takes the number of minutes in 4 hours—which is "
240 minutes"—and add "
30 minutes" to that number; as follows:
→ "
240 minutes + 30 minutes " ;
to get: "
270 minutes " .
_______________________________________________________ → There are "
270 minutes" in "
4 hours and 30 minutes" .
_______________________________________________________
The answer is: "
270 minutes " .
_______________________________________________________