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zepelin [54]
3 years ago
15

What is the surface area of the triangular prism can someone please please help me

Mathematics
1 answer:
sveta [45]3 years ago
5 0
To solve this problem, we need to know the formula of the surface area of a triangular prism. The formula is: A = 2A_{B} + (a+b+c) * h

Now we can substitute values and solve

A = 2(0.5 * 4 * 3) + (3+4+5) * 20

A = 12 + 240

A = 252

That means that the answer to this question is 252 square feet. 
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Komok [63]

Answer:

x° = 37.13°

Step-by-step explanation:

13.4 = cathetus opposite the angle "x°"

22.4 = hypotenuse

sin(x^{o}) =\frac{13.4}{22.2}=0.6036

x^{o} =sin^{-1} (0.6036)=37.13^{o}

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PLEASE HELP ASAP: highest amount of points
butalik [34]

Answer:

$778.46 is the bi-weekly net pay

Step-by-step explanation:

Net pay  is the gross pay minus taxes

Net pay = gross pay - gross pay * tax rate

Simplifying this equation by factoring out gross pay

Net pay = gross pay (1- tax rate)


Substituting this in

Net pay = gross pay (1- tax rate)

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hours worked = 23000

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Net pay = 20240

But this is per year, and we want it bi weekly

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3 years ago
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In triangle ABC, angle A=50°, angle C=65°. Point F is on AC such that, BF is perpendicular to AC. D is a point on BF (extended)
LiRa [457]

Answer:

The length of EF is 5.29

Step-by-step explanation:

If BC = 12 then;

FB = 12 × sin65 = 10.876

BA = FB/(sin50) = 10.876/(sin50) = 14.2

BD = AB (Sides of isosceles triangle) = 14.2

∴ DF = BD + FB = 10.876 + 14.2 = 25.07

∠F C D = tan⁻¹(D F/F C) =  tan⁻¹(25.07/(12×cos65)) = 78.6

∠F A D = tan⁻¹(D F/A F) =  tan⁻¹(25.07/(14.2×cos50)) = 70

∴ ∠D = 180 - (78.6° + 70°) = 31.4°

AE = AD × sin31.4° = 2×AB×cos(70° - 50°) × sin31.4

∴ AE =  2×14.2×cos(20°) × sin31.4 = 13.92

EC = AC × cos78.6° = (AB×cos50 + BC×cos65)×cos78.6° = 2.815

Therefore, from cosine rule, a² = b² + c² - 2·b·c × cos(A)

Hence, we have;

EF² = EC² + FC² - 2 × EC × FC ×cos∠FCD (Cosine rule)

That is, EF² = 2.815² + (12×cos65)² - 2 × 2.815× (12×cos65) ×cos78.6°

EF² = 27.98

∴EF = √27.98 = 5.29.

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