Question

Solve for x: x^2 + 28x = 60

Answer 1

For this case we have a quadratic equation, $x ^ 2 + 28x-60 = 0$, of the form $ax ^ 2 + bx + c = 0$

Where:

$a = 1\\b = 28\\c = -60$

We can solve the equation by factoring, that is, we bias two numbers that multiplied give as a result -60 and added as a result 28.

These numbers are:

$+30\ and\ -2\\+ 30-2 = + 28\\+ 30 * -2 + -60$

Then, the factorization is given by:

$(x-2) (x + 30) = 0$

The roots are:

$x_ {1} = 2\\x_ {2} = - 30$

Answer:

$x_ {1} = 2\\x_ {2} = - 30$