Answer:
b and d i think.
Step-by-step explanation:
B passes through the ordered pairs negative 3, 8 and 2, negative 7.
D passes through the ordered pairs 1, 4 and negative 4, negative 1 and is extrapolated further in the quadrant.
Answer:
x=5
Step-by-step explanation:
So first you would subtract 2x from both sides to get:
1x = 5
Then you divide both sides by 1:
x = 5
Each centimeter on the map represents 20 miles in real life. Similarly, every twenty miles in real life would be represented as 1 centimeter on the map.
Answer:
Tristan has a 17/24 lb fraction of a pound of grapes now.
Step-by-step explanation:
Given
- The number of grapes Tristan had at home = 1/3 lb
- The number of grapes Tristan had at the store = 3/8 lb
To determine
What fraction of a pound of grapes does Tristan have now?
In order to get the total fraction of a pound of grapes, all we need is to add the number of grapes Tristan had at home and the number of grapes Tristan had at the store.
i.e.
Current number grapes = 1/3 + 3/8
Least Common Multiple of 3, 8: 24
Adjust fractions based on L.C.M
= 8/24 + 9/24
Apply the fraction rule: 
= (8 + 9) / 24
= 17/24 lb
Therefore, Tristan has a 17/24 lb fraction of a pound of grapes now.
Although the formula looks involved, the key here is looking to see where the information goes.
We are given all the pieces but need to convert mph to ft/s to use the formula. Let's do it with 1 mph so that we have a ratio to use. We and solve a unit conversion problem.

That ratio tells us that 1 mph is 1.466666 ft/s. Now we solve two proportions.
1 mph / 1.466666 feet per second = 60 mph / x feet per second.
1x = (60)(1.466666)
So x = 88 feet per second.
Next, We repeat for 24 mph.
1 mph / 1.46666 feet per second = 24 mph / x feet per second.
1x = (1.4666666)(24)
x = 35.2 feet per second
Now we have the found appropriate V₁ and V₂. V₁ > V₂, so V₁ is 88 ft/s and V₂ is 35.2 ft/s. The problem tells us θ = 2.3 degrees, K₁ = .4 and K₂ = .06. The rest of the problem is calculator work. Start by substituting our degree measure of 2.3 degrees and the given values in the problem for V₁, V₂, K₁, and K₂
![D = \frac{1.05[(88)^{2}-(35.2)^{2}]}{64.4(.4+.06 + (sin 2.3))}](https://tex.z-dn.net/?f=D%20%3D%20%5Cfrac%7B1.05%5B%2888%29%5E%7B2%7D-%2835.2%29%5E%7B2%7D%5D%7D%7B64.4%28.4%2B.06%20%2B%20%28sin%202.3%29%29%7D)
![D = \frac{1.05[(7744-1239.04]}{64.4(.46 + (sin 2.3))}](https://tex.z-dn.net/?f=D%20%3D%20%5Cfrac%7B1.05%5B%287744-1239.04%5D%7D%7B64.4%28.46%20%2B%20%28sin%202.3%29%29%7D)


D = 6830.208 / 32.208372
D = 212.0631 = 212 (to the nearest foot)
Thus the car needs 212 feet to stop.