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Maslowich
4 years ago
8

A. The null and alternative hypotheses are given. Determine whether the hypothesis test is​ left-tailed, right-tailed, or​ two-t

ailed. What parameter is being​ tested? H 0​: σ = 130 H 1​: σ < 130B. Is the hypothesis test left-tailed, right-tailed, or two-tailed?C. What parameter is being tested?O Population proportionO Population standard deviationO Population mean
Mathematics
1 answer:
krok68 [10]4 years ago
7 0

Answer: B. The hypothesis test left-tailed.

C.  Population standard deviation

Step-by-step explanation:

Parameters are the variables that are used to test different espects of the researcher.

The null and alternative hypotheses are given. as

H_0:\sigma=130\\\\H_1:\sigma

Type of test (left-tailed, right-tailed, or​ two-tailed.) basically depends on the alternative hypothesis.

Here, the alternative hypothesis (H_1) is left-tailed , so the test is a left -tailed test.

We can clearly see that the parameter is being tested here is Population standard deviation (\sigma) .

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Solve one third plus seven ninths equals blank
ruslelena [56]

Answer:

10/9ths or 1& 1/9

Step-by-step explanation:

1/3 + 7/9 =

× 9/9. × 3/3

9/27 + 21/27 = 30/27

OR 1 & 1/9

5 0
4 years ago
Will give brainliest
Cloud [144]

Answer:

x = 90 degrees, right triangle

Step-by-step explanation:

48 + 42 + x = 180

90 + x = 180

180 - 90 = x

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3 0
3 years ago
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Add. (3b + 5) + (2b + 4) *
gtnhenbr [62]
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6 0
3 years ago
The volume of a box is 5x^3 + 20x^2 + 15x cm^3. If the height of the box is 5x cm, find the width and length of the box.
Annette [7]

Answer:

The product of the Width and Length is x^2 + 4x + 3 cm^2.

Step-by-step explanation:

The volume of a box = 5x^3 + 20x^2 + 15x cm^3.

Volume of a Box = W*L*H       [Width(W), Length(L), and Height(H)]

W*L*(5x) = 5x^3 + 20x^2 + 15x cm^3

W*L = (5x^3 + 20x^2 + 15x cm^3)/5x cm

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We know the area of the base of the box (W*L).  It is x^2 + 4x + 3 cm^2.

To find the actual width and length, we need to know one of the variables, L or W.  Without that, all we can say is that their product (W*L) is x^2 + 4x + 3 cm^2.

8 0
2 years ago
5a+5b=25 and -5a+5b=35
Alex_Xolod [135]

add the two equations together

5a+5b=25

-5a+5b=35

------------------

 0  + 10b =60

divide by 10

b=6

5a + 5b = 25

5a +5(6) = 25

5a +30 =25

subtract 30 from each side

5a =-5

divide by 5

a = -1

Answer (-1,6)

or a=-1 b=6

3 0
3 years ago
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