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timurjin [86]
3 years ago
14

Do y’all have a Factor For 7and10

Mathematics
1 answer:
Julli [10]3 years ago
4 0

Assuming by "factor" you mean a number that can be multiplied by another to make 7 or 10, then there is no other factor other than 1 as 7 is a prime number.

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PLEASE HELP FAST Which of the following is a step in simplifying the expression? ​
Ainat [17]

Answer:

A

Step-by-step explanation:

i am pretty sure its A because on the top one their is one negative and all of the other one are positive.

6 0
3 years ago
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Find an orderd pair (x,y) that is a solution to the equation 4x+y=9
Aleksandr [31]

Answer:

Below in bold.

Step-by-step explanation:

4x + y = 9

Let's put x = 0 then:

4(0) + y = 9

0 + y = 9

y = 9

So one. ordered pair that is a solution is (0, 9)

7 0
3 years ago
A car is driving at 40 kilometers per hour. How far, in meters, does it travel in 2 seconds?
Troyanec [42]

Answer:

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How to simplify this expression
dexar [7]

Answer:

  \dfrac{x+2}{x+1}

Step-by-step explanation:

Factor the numerator and cancel common factors from numerator and denominator.

  \dfrac{x^2-4}{(x-2)(x+1)}=\dfrac{(x-2)(x+2)}{(x-2)(x+1)}=\dfrac{x+2}{x+1}

5 0
3 years ago
The mean annual income for people in a certain city is 37 thousand dollars, with a standard deviation of 28 thousand dollars. A
Aloiza [94]

Answer:

P( 31 < \bar X< 41)

And we can ue the z score formula given by:

z= \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using this formula we got for the limits:

z = \frac{31-37}{\frac{28}{\sqrt{50}}}= -1.515

z = \frac{41-37}{\frac{28}{\sqrt{50}}}= 1.01

So we want to find this probability:

P(-1.515

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the annual income of a population, and for this case we know the following info:

\mu=37 and \sigma=28  and we are omitting the zeros from the thousand to simplify calculations

We select a sample size of n=50>30.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want to find this probability:

P( 31 < \bar X< 41)

And we can ue the z score formula given by:

z= \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using this formula we got for the limits:

z = \frac{31-37}{\frac{28}{\sqrt{50}}}= -1.515

z = \frac{41-37}{\frac{28}{\sqrt{50}}}= 1.01

So we want to find this probability:

P(-1.515

4 0
3 years ago
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