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3 years ago

Can someone help me with this??

Mathematics

1 answer:

Ghella [55]3 years ago

7 0

No matter how long they rent for, they have to pay at least 20. Any additional hour is 10. But since it says “part of an hour” that makes this really easy.
1) $30 (the first hour is 20, the second hour is 10 even though they didn’t use the full hour completely)
2)$30 (same situation as 1)
3)$40 (20+10+10)
4)$50 (20+10+10+10 even though that additional hour was only 1 min)
5) Below five hours and above three hours. If you’re spending $50 you rented it within at least four hours. I hope that makes sense

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The literals are; a, b, and c

The constants are; c, and 3

The variables are; x, and y

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The given equation is a·x² + b·x + c - y + 3 = 0

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3 years ago

Suppose 241 subjects are treated with a drug that is used to treat pain and 54 of them developed nausea. Use a 0.05 significance

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Answer:

Null Hypothesis, $H_0$ : p = 0.20

Alternate Hypothesis, $H_a$ : p > 0.20

Step-by-step explanation:

We are given that 241 subjects are treated with a drug that is used to treat pain and 54 of them developed nausea.

We have to use a 0.05 significance level to test the claim that more than 20% of users develop nausea.

Let p = population proportion of users who develop nausea

So, Null Hypothesis, $H_0$ : p = 0.20

Alternate Hypothesis, $H_a$ : p > 0.20

Here, null hypothesis states that 20% of users develop nausea.

And alternate hypothesis states that more than 20% of users develop nausea.

The test statistics that would be used here is One-sample z proportion test statistics.

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = proportion of users who develop nausea in a sample of 241 subjects = $\frac{54}{241}$

n = sample of subjects = 241

So, the above hypothesis would be appropriate to conduct the test.

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4 years ago