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3 years ago

10

Find the area contained between

le=" {y }^{2} = x" alt=" {y }^{2} = x" align="absmiddle" class="latex-formula">
and
$y = {x}^{2}$

1 answer:

marissa [1.9K]3 years ago

6 0

The area is given by

$\displaystyle\int_0^1\sqrt x-x^2\,\mathrm dx=\dfrac23x^{3/2}-\dfrac13x^3\bigg|_{x=0}^{x=1}$

so the area is

$\dfrac23-\dfrac13=\dfrac13$

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Find (f•f) (0)<br> F(x)=3x-2

NNADVOKAT [17]

Answer: (f·f)(0) = 4

(fof)(0) = -8

<u>Step-by-step explanation:</u>

f(x) = 3x - 2

(f·f)(x) = (3x - 2)(3x - 2)

= 9x² - 12x + 4

(f·f)(0) = 9(0)² - 12(0) + 4

= 4

(fof) = 3(3x - 2) - 2

= 9x - 8

(fof)(0) = 9(0) - 8

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<em>I wasn't sure if you wanted multiplication or composition so I solved both</em>

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3 years ago

Solve for f<br> -f +2 + 4f = 8 - 3f

Ulleksa [173]

Answer:

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Step-by-step explanation:

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3 years ago

HELP NEEDED PLEASE!!!

postnew [5]

Using vector concepts, it is found that:

The component form is of approximately (-9.58, 7,22). It means that the ship is about 9.58 miles to the west and about 7.22 miles to the north of where the ship left the port.

<h3>How can a vector be represented in component notation?</h3>

Given a magnitude M and angle $\theta$ , then a vector V can be represented as follows in component notation:

$V = (M\cos{\theta}, M\sin{\theta})$

In this problem, the magnitude and the angle are given, respectively, by:

$M = 12, \theta = 143^\circ$

Hence:

V = [12cos(143º), 12sin(143º)] = (-9.58, 7,22).

Which means a displacement of 9.58 miles to the west(negative x = west) and 7.22 miles to the north(positive y = north).

The component form is of approximately (-9.58, 7,22). It means that the ship is about 9.58 miles to the west and about 7.22 miles to the north of where the ship left the port.

More can be learned about vectors at brainly.com/question/24606590

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2 years ago

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expeople1 [14]

Answer:

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Step-by-step explanation:

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3 years ago

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nignag [31]

Answer:

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Step-by-step explanation:

the point makes a decimal a decimal

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