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krek1111 [17]
3 years ago
10

I need it ASAP, brainliest to whoever answers correctly!

Computers and Technology
1 answer:
velikii [3]3 years ago
6 0

Answer:

E

Explanation:

i think it is E because if you think about it they don't make everything accurate on normal mapping its just to give you an idea of where to go or find.

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earnstyle [38]
Because machine (cpu) can only execute machine code(language).
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4 years ago
PLEASE HELP ITS CODING AND I INCLUDED A SCREENSHOT OF WHAT TO DO
Anettt [7]

def even_checker(lst):

   for x in lst:

       if x%2==0:

           print(x)

l = [1,2,3,4,5,6,7,8,9,10]

even_checker(l)

I wrote my code in python 3.8. I hope this helps.

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3 years ago
How do you create code on scratch?
lina2011 [118]
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3 0
3 years ago
Read 2 more answers
Size of a request header field exceeds server limit.
garri49 [273]
Try to Increase the value for the directive LimitRequestFieldSize in the httpd.conf:


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8 0
3 years ago
In this lab you will write a C program to sort an array of strings. The program will: Create an array of 50 strings; each string
andrezito [222]

Answer:

See explaination

Explanation:

#include <stdio.h>

#include <stdlib.h>

#include <string.h>

void swap(char *arr[], int i, int minIdx)

{

char temp[30];

strcpy(temp, arr[i]);

strcpy(arr[i], arr[minIdx]);

strcpy(arr[minIdx], temp);

}

void sort(char *arr[], int n)

{

for (int i = 0; i < n - 1; i++)

{

int minIdx = i;

int minV = 10000;

char min[30];

strcpy(min, arr[i]);

for (int j = i + 1; j < n; j++)

{

int a = strcmp(min, arr[j]);

if (a < 0)

{

strcpy(min, arr[i]);

minIdx = j;

}

}

swap(arr, i, minIdx);

}

}

void print(char *arr[], int n)

{

for (int i = 0; i < n; i++)

printf("%s", arr[i]);

}

void read(char *arr[], int *n)

{

FILE *file = fopen("strings.dat", "r");

char line[30];

*n = 0;

printf("Reading from file...\n");

while (fgets(line, 30, file))

{

strcpy(arr[(*n)++], line);

}

print(arr, *n);

}

int main(int argc, char const *argv[])

{

char *arr[50];

for (int i = 0; i < 50; i++)

arr[i] = (char *)malloc(sizeof(char) * 30);

int len;

int n = 0;

read(arr, &n);

printf("\n-------------------------\nAfter sorting\n");

sort(arr, n);

print(arr, n);

}

6 0
3 years ago
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