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grandymaker [24]
3 years ago
10

What is 175% of 14.2

Mathematics
2 answers:
VMariaS [17]3 years ago
8 0

Hey!


To find the answer, change 175% to a decimal and multiply by 14.2


To change percents to decimals, remove the % sign and move the decimal point to places to the left.


175 \% = 1.75


Now multiply


1.75 \times 14.2 = 24.85


\framebox{Answer = 24.85}

LUCKY_DIMON [66]3 years ago
7 0
175% of 14.2 is saying that

1.75(14.2)=24.9

Any questions please just ask. Thank you.
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4974 is divisible by what number?​
Vera_Pavlovna [14]

Answer:

Divisibility of 4974

The number 4,974 is divisible by 2, 3 and 6.

6 0
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The trinket store is open for 14 hours per day. They sell an average of 5 trinkets per hour. The back storeroom currently has 56
tekilochka [14]
Q1)
write the equation that estimates the number of trinkets T that will be in the storeroom after H hours
Initially the number of trinkets available = 560
every hour they sell an average of 5 trinkets 
therefore in H hours, number of trinkets that will be sold = 5 trinkets/hr * H hrs
number of trinkets sold in H hours = 5H
the remaining number of trinkets = T
T = number of trinkets initially available - number of trinkets sold 

T = 560 -5H

Q2) 
How many days will it take to run out of trinkets 
number of trinkets sold per hour - 5 
number of hours the shop is open for - 14 hours / day
during one day number of trinkets sold - 5 trinkets/hr x 14 hrs/ day
                                                              = 70 trinkets per day
there are 560 trinkets available 
and if 70 trinkets are sold per day 
number of days it takes to sell 560 trinkets 
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the third response is correct - 1) T = 560 -5H
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3 0
4 years ago
Root 3 cosec140° - sec140°=4<br>prove that<br><br>​
Lorico [155]

Answer:

Step-by-step explanation:

We are to show that \sqrt{3} cosec140^{0} - sec140^{0} = 4\\

<u>Proof:</u>

From trigonometry identity;

cosec \theta = \frac{1}{sin\theta} \\sec\theta = \frac{1}{cos\theta}

\sqrt{3} cosec140^{0} - sec140^{0} \\= \frac{\sqrt{3} }{sin140} - \frac{1}{cos140} \\= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\

From trigonometry, 2sinAcosA = Sin2A

= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\\\=  \frac{\sqrt{3}cos140-sin140 }{sin280/2}\\=  \frac{4(\sqrt{3}/2cos140-1/2sin140) }{2sin280}\\\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{sin280}\\since sin420 = \sqrt{3}/2 \ and \ cos420 = 1/2  \\ then\\\frac{4(sin420cos140-cos420sin140) }{sin280}

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Dominik [7]
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1.) 7921 pi squared
2.) 24,871.94 feet squared
Hope this helps
5 0
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