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Marina86 [1]
3 years ago
7

Before becoming romantically involved with a coworker you should

Computers and Technology
2 answers:
astra-53 [7]3 years ago
7 0
You should make sure no one is looking and make sure you have protection
snow_lady [41]3 years ago
5 0
Get to know them ask if they like anyone if they don't say anything it might be you ask there friends if they like you or not.
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During the course of execution of a program, the processor will increment the contents of the instruction register (program coun
Oksana_A [137]
Bdbdbdhdhdhdhdjdbsbbrvrvrrvrvrvfvfvvfvfvfvfvfhdhdhdhdhdhdhhdududududududuebebbedvdvd I known why ahh it happened
8 0
3 years ago
Write a short note on attributes in HTML.<br> If you answer this i will mark you as BRAINLIST
Hunter-Best [27]

Answer:

Explanation:

HTML attributes are a modifier of an HTML element type. An attribute either modifies the default functionality of an element type or provides functionality to certain element types unable to function correctly without them. In HTML syntax, an attribute is added to an HTML start tag.

4 0
3 years ago
Transistors contain a huge number of integrated circuits <br><br> a. true or <br> b. false
malfutka [58]
False. Integrated circuits have transistors within them, not the other way around
6 0
3 years ago
Primary U.S. interstate highways are numbered 1-99. Odd numbers (like the 5 or 95) go north/south, and events (like the 10 or 90
Norma-Jean [14]

Answer:

The C code for the problem is given below

Explanation:

#include <stdio.h>

int main() {

   int highwayNumber;

   int primaryNumber;

   scanf("%d", &highwayNumber);

   if (highwayNumber >= 1 && highwayNumber <= 999) {

       if (highwayNumber <= 99) {

           if (highwayNumber % 2 == 0) {

               printf("I-%d is primary, going east/west.\n", highwayNumber);

           } else {

               printf("I-%d is primary, going north/south.\n", highwayNumber);

           }

       } else {

           primaryNumber = highwayNumber;

           highwayNumber %= 100;

           if (highwayNumber % 2 == 0) {

               printf("I-%d is auxiliary, serving the I-%d, going east/west.\n", primaryNumber, highwayNumber);

           } else {

               printf("I-%d is auxiliary, serving the I-%d, going north/south.\n", primaryNumber, highwayNumber);

           }

       }

   } else {

       printf("%d is not a valid interstate highway number.\n", highwayNumber);

   }

   return 0;

}

4 0
3 years ago
Read 2 more answers
Write a function with two parameters, prefix (a string, using the string class from ) and levels (an unsigned integer). The func
Allisa [31]

Answer:

Here is the program:

#include <iostream>  //to use input output functions

#include <string>  // to use functions to manipulate strings

using namespace std;  //to identify objects cin cout

void function(string prefix, unsigned int levels){  // function that takes two parameters, a string, using the string class and levels an unsigned integer

   if (levels == 0) {  //if number of levels is equal to 0

       cout << prefix << endl;  //displays the value of prefix

       return;    }  

  for (int i = 1; i <=9 ; i++){  //iterates 1 through 9 times

       string sections = (levels == 1 ? "" : ".");  //if the number of levels is equal to 1 then empty space in sections variable otherwise stores a dot

       string output = prefix +  std::to_string(i) + sections;   // displays the string prefix followed by the section numbers. Here to_string is used to convert integer to string

       function(output, levels - 1);   } }   //calls function by passing the resultant string and levels-1  recursively to print the string prefix followed by section numbers

int main() {  // start of main function

   int level = 2;  //determines the number of levels

   function("BOX", level);  } //calls function by passing the string prefix and level value

Explanation:

The program has a function named function() that takes two parameters, prefix (a string, using the string class from ) and levels (an unsigned integer). The function prints the string prefix followed by "section numbers" of the form 1.1., 1.2., 1.3., and so on. The levels argument determines how many levels the section numbers have. If the value of levels is 0 means there is 0 level then the value of prefix is printed. The for loop iterates '1' through '9' times for number of digits in each level. If the number of levels is 1 then space is printed otherwise a dot is printed. The function() calls itself recursively to print the prefix string followed by section numbers.

Let us suppose that prefix = "BOX" and level = 1

If level = 1 then the loop for (int i = 1; i <=9 ; i++) works as follows:

At first iteration:

i = 1

i <=9 is true because value of i is 1

string sections = (levels == 1 ? "" : "."); this statement checks if the levels is equal to 1. It is true so empty space is stored in sections variable so,

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement has prefix i.e BOX plus value of i which is 1 and this int value is converted to string by to_string() method plus sections has an empty space. So this statement becomes

string output = BOX + 1  

So this concatenates BOX with 1 hence output becomes:

output = BOX1

At second iteration:

i = 2

i <=9 is true because value of i is 2

string sections = (levels == 1 ? "" : "."); is true so

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement becomes

string output = BOX + 2  

So this concatenates BOX with 1 hence output becomes:

output = BOX2

At third iteration:

i = 3

i <=9 is true because value of i is 3

string sections = (levels == 1 ? "" : "."); is true so

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement becomes

string output = BOX + 3  

So this concatenates BOX with 1 hence output becomes:

output = BOX3

Now at each iteration the prefix string BOX is concatenated and printed along with the value of i. So at last iteration:

At last iteration:

i = 9

i ==9 is true because value of i is 9

string sections = (levels == 1 ? "" : "."); is true so

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement becomes

string output = BOX + 9  

So this concatenates BOX with 1 hence output becomes:

output = BOX9

After this the loop breaks at i = 10 because the condition i<=9 becomes false. So the output of the entire program is:

BOX1                                                                                                                                          BOX2                                                                                                                                          BOX3                                                                                                                                          BOX4                                                                                                                                          BOX5                                                                                                                                          BOX6                                                                                                                                          BOX7                                                                                                                                          BOX8                                                                                                                                          BOX9  

The program along with the output is attached.

4 0
3 years ago
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