Answer:
int main()
{
double pH;
int neutral;
int base;
int acid;
cout<<"Enter a pH Value";
cin>> pH;
if(pH<7.0){
neutral =0;
base=0;
acid= 1;
}
else if (pH=7.0){
neutral =1;
base=0;
acid= 0;
}
else{
neutral =0;
base=1;
acid= 0;
}
cout <<"The neutral, Base and Acid Values are: "<<neutral<<","<<base<<","<<acid<<" Respectively"<<endl;
return 0;
}
Explanation:
Using multiple if/elseif/else statement the following problem is solved with C++
Yes :) I totally agree with the person above me ^
Answer:
#include <iostream>
#include <cmath>
using namespace std;
int main()
{
double num1, num2, num3, num4, num5, sum = 0;
cout << "Input: ";
cin >> num1 >> num2 >> num3 >> num4 >> num5;
sum = num1 + num2 + num3 + num4 + num5;
cout << "Output: " << static_cast<int>(round(sum)) << endl;
return 0;
}
Explanation:
Include cmath to use the round function
Declare the variables
Get the five numbers from the user
Sum them and assign the result to the sum
Round the sum using the round function, and convert the sum to an integer using static_cast statement
Print the sum
