50+75-82*6=50+75-492=125-492=-367
82*6=492
Volume of a cone = π r² h/3
I envisioned a cone inside a cube. I only identified the necessary value to compute for the exact volume of the largest cone.
Edges of the cube is 10 inches. When the circle part of the cone is placed in the circle, the diameter would be 10 inches also. I divided it by 2 to get the value of the radius, resulting to 5 inches.
The height of the cone is also the height of the cube. Thus, it is 10 inches.
Volume of the cone = 3.14 * (5in)² * 10in/3
V = 3.14 * 25in² * 3.33 in
V = 261.405 in³ or 261.41 in³ VOLUME OF THE LARGEST CONE THAT CAN FIT IN A 10 INCH CUBE
Let I am interest, r rate, t time and p principle,
l= prt
l= 5500(.115)(5 )= $3162.5 is the total amount of interest to pay.
1 US = 1.09 Australian
divide by 1.09 on both sides to find how much a 1 Australian dollar is worth.
1/1.09 = 1 Australian dollar
1 Australian dollar = 0.92 US dollar
mulitply 35 on both sides of the equation
35 Australian = 35 (0.92) = 32.2 US dollars
I think I have the answer let me just double check my work okay!
