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galben [10]
3 years ago
8

Evaluate the expression below if x=-1 and y=3. 3x²-y²

Mathematics
2 answers:
svlad2 [7]3 years ago
8 0
The answer is -12 I believe
Dmitry [639]3 years ago
7 0

Answer:

-6

Step-by-step explanation:

3x² - y²

plug in x and y

3(-1)² - (3)²

according to PEMDAS, solve the exponents first.

3(1) - 9

multiply

3 - 9

subtract

= -6

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Answer:

its green so you got it right

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Step-by-step explanation:

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2 years ago
Use the identity (x^2+y^2)^2=(x^2−y^2)^2+(2xy)^2 to determine the sum of the squares of two numbers if the difference of the squ
marissa [1.9K]

Answer:

Step-by-step explanation:

(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2

Adding and substracting 2x^2y^2

We get

(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2 +2x^2y^2-2x^2y^2

And we know a^2-2ab+b^2=(a-b)^2

So we identify (x^2)^2 as a^2 ,(y^2)^2 as b^2 and -2x^2y^2 as - 2ab. So we can rewrite (x^2+y^2)^2=(x^2 - y^2)^2 + 2x^2y^2 + 2x^2y^2= (x^2 - y^2)^2+4x^2y^2= (x^2 - y^2)^2+2^2x^2y^2

Moreever we know (a·b·c)^2=a^2·b^2·c^2 than means 2^2x^2y^2=(2x·y)^2

And (x^2+y^2)^2=(x^2 - y^2)^2 + (2x·y)^2

5 0
3 years ago
Calculate δe, if q= 0.769 kj and w= -860 j .
Andreyy89
<span>Best Answer: 1) Q is positive therefore the process is endothermic. .769kj+-.810kj=-.041kj 2) Heat is released meaning it is exothermic. -66.9kj+45=-21.9kj 3) 7.29kj. Endothermic.</span>
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2 years ago
Find the slope of the line that passes through the points (0, -3) and (-4,1).
kozerog [31]

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In this case:

y_{2} = 1\\ y_{1} }= -3\\x_{2} = -4\\x_{1} = 0

so...

\frac{1 - (-3)}{-4 - 0}

\frac{4}{-4}

-1 <<<The slope

Hope this helped!

~Just a girl in love with Shawn Mendes

7 0
2 years ago
Read 2 more answers
Describe fully the single
Lerok [7]

Answer:

Rotation 90⁰ clockwise about point (-1,-1)

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2 years ago
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