Question

Consider the balanced chemical equation, MgCl2(aq) + 2AgF(aq) → 2AgCl(s) + MgF2(aq) If both reactants are completely consumed and we produce 20 formula units of AgCl, how many ions of Mg and F did we start with? A) 10 ions of Mg and 20 ions of F B) 10 ions of Mg and 10 ions of F C) 20 ions of Mg and 10 ions of F D) 20 ions of Mg and 20 ions of F

Answer 1

Answer:

A

Explanation:

MgCl2 + 2AgF > 2AgCl + MgF2

Nope ratio= 1:2:2:1

So 20cm3 of AgCl will yield 10Cm3 of MgCl2 and 20cm3 of AgF according to gay lussac law.

Ionization of MgCl2

MgCl2--> Mg2+ + 2Cl-

1 :. 1 : 2

10cm3 : 10cm3 : 20cm3

Ionization of 2AgF

2AgF---> Ag2+ + 2F-

2 : 1 : 2

20cm3 10cm3 20cm3

So we started with 10cm3 of Mg ion and 20cm3 of Florida ion

Answer 2

I believe the answer is A) 10 ions of Mg and 20 ions of F