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Talja [164]
3 years ago
6

Please help there more than one right answer please help the last answer choices is

Mathematics
1 answer:
aliya0001 [1]3 years ago
4 0

A(t) = 500(1.0325)^t

500 is the initial deposit, t=0, A(0)=500

3.25% is the interest rate

t is in years

Let's go through the choices.

After 1 year ... A(1)=500.  Don't check; it's A(0) that equals 500, A(1) is bigger.

The rate is 1.03%.   Don't check; the base being exponentiated is 1 plus the rate.

Rate is 3.25%.  TRUE   that's why we have 1 + 0.0325 as the base.

Rate is 5%.   Don't check.

Only one right answer.

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Solve this system of equations using the elimination method.
Ray Of Light [21]

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Step-by-step explanation:

Our system of linear equations is:

6x + 2y = 18

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When we solve by elimination, we're essentially "eliminating" a variable so that we can solve for other more easily. Here, let's eliminate the y variable by adding the two equations together:

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3 years ago
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Weatherwise is a magazine published by the American Meteorological Society. One issue gives a rating system used to classify Nor
gogolik [260]

Answer:

Step-by-step explanation:

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

µ = 16.4

For the alternative hypothesis,

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Since the population standard deviation is given, z score would be determined from the normal distribution table. The formula is

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σ = population standard deviation

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From the information given,

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x = 17.1

σ = 3.1 feet

n = 31

z = (17.1 - 16.4)/(3.1/√31) = 0.89

The calculated test statistic is 0.89 for the right tail and - 0.89 for the left tail

Since α = 0.01, the critical value is determined from the normal distribution table.

For the left, α/2 = 0.01/2 = 0.005

The z score for an area to the left of 0.005 is - 2.575

For the right, α/2 = 1 - 0.005 = 0.995

The z score for an area to the right of 0.995 is 2.575

In order to reject the null hypothesis, the test statistic must be smaller than - 2.575 or greater than 2.575

Since - 0.89 > - 2.575 and 0.89 < 2.575, we would fail to reject the null hypothesis.

Therefore, this information does not suggest that the storm is (perhaps temporarily) increasing above the severe rating

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