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Vikki [24]
4 years ago
15

A math class is playing a game with 16 questions that uses the bored below.Once a question is called,it is not called again.Find

the probability of the first two questions called.
Mathematics
2 answers:
GREYUIT [131]4 years ago
7 0

Answer:

The answer to your question is 16. hope this helps. thank you :)

Step-by-step explanation:

plz mark brainliest!

Semmy [17]4 years ago
5 0

Answer:

16

Step-by-step explanation:

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What are the equations of the asymptotes of the graph of f(x)=(5/x+7)−8 ?
ludmilkaskok [199]

Answer:

\mathrm{Vertical}:\:x=0,\:\mathrm{Horizontal}:\:y=-1

The graph of the function is also attached.

Step-by-step explanation:

Considering the expression

\:f\left(x\right)=\left(\frac{5}{x}+7\right)-8\:\:

\mathrm{Simplify}\:\frac{5}{x}+7-8:\quad \frac{5}{x}-1

\mathrm{Vertical\:asymptotes\:of\:}\frac{5}{x}-1:

Go over every undefined point x = a and check if at least one of the following statement is true.

\lim _{x\to a^-}f\left(x\right)=\pm \infty

\lim _{x\to a^+}f\left(x\right)=\pm \infty

\mathrm{Take\:the\:denominator\left(s\right)\:of\:}\frac{5}{x}-1\mathrm{\:and\:compare\:to\:zero}

x=0

The following points are undefined

x=0

\mathrm{The\:vertical\:asymptotes\:are:}

x=0

\mathrm{Horizontal\:Asymptotes\:of\:}\frac{5}{x}-1:

\mathrm{Check\:if\:at\:}x\to \pm \infty \mathrm{\:the\:function\:}y=\frac{5}{x}-1\mathrm{\:behaves\:as\:a\:line,\:}y=mx+b

\mathrm{Find\:an\:asymptote\:for\:}x\to -\infty \::

\lim _{x\to -\infty \:}\frac{f\left(x\right)}{x}=\lim _{x\to -\infty \:}\frac{\frac{5}{x}-1}{x}=0

\lim _{x\to -\infty \:}f\left(x\right)-mx=\lim _{x\to -\infty \:}\frac{5}{x}-1-0x=-1

y=-1

\mathrm{Find\:an\:asymptote\:for\:}x\to \infty:

\lim _{x\to \infty \:}\frac{f\left(x\right)}{x}=\lim _{x\to \infty \:}\frac{\frac{5}{x}-1}{x}=0

\lim _{x\to \infty \:}f\left(x\right)-mx=\lim _{x\to \infty \:}\frac{5}{x}-1-0x=-1

y=-1

\mathrm{The\:horizontal\:asymptote\:is:}

y=-1

Therefore,

\mathrm{Vertical}:\:x=0,\:\mathrm{Horizontal}:\:y=-1

The graph of the function is also attached.

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