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liubo4ka [24]
3 years ago
10

Dog A barks 20 times in 2 minutes, Dog B barks 45 times in 5 minutes, and Dog C barks 66 times in 6 minutes. Which dog barks the

most number of times per minute?
Dog A barks the most times per minute.

Dog B barks the most times per minute.

Dog C barks the most times per minute.

Dog A and Dog B bark the most times per minute.

Dog B and Dog C bark the most times per minute.Dog A barks 20 times in 2 minutes, Dog B barks 45 times in 5 minutes, and Dog C barks 66 times in 6 minutes. Which dog barks the most number of times per minute?

Dog A barks the most times per minute.

Dog B barks the most times per minute.

Dog C barks the most times per minute.

Dog A and Dog B bark the most times per minute.

Dog B and Dog C bark the most times per minute.
Mathematics
2 answers:
PolarNik [594]3 years ago
7 0

Answer:

the answer is c

Step-by-step explanation: Because you need to find out how many times the dog barks in one minute DOG A 20times divided by 2 minutes is 10 per minute 45/5 is 9 66/6 is 11

DerKrebs [107]3 years ago
5 0

Answer:

Dog C barks the most times per minute.

Step-by-step explanation:

Dog A barks 10 times per minute. 20/2 = 10

Dog B barks 9 times per minute. 45/5 = 9

Dog C barks 11 times per minute. 66/6 = 11

11 is greater than 10 and 9, therefore, Dog C barks the most.

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maks197457 [2]
First, recall that Gaussian quadrature is based around integrating a function over the interval [-1,1], so transform the function argument accordingly to change the integral over [1,5] to an equivalent one over [-1,1].

x=2t+3\iff t=\dfrac x2-\dfrac32\implies2\mathrm dt=\mathrm dx
x=1\implies t=\dfrac{2-6}4=-1
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So,

\displaystyle\int_{x=1}^{x=5}\sin x^2\,\mathrm dx=\displaystyle2\int_{t=-1}^{t=1}\sin(2t+3)^2\,\mathrm dt

Let f(t)=2\sin(2t+3)^2. With n=4, we're looking for coefficients c_i and nodes x_i, with 1\le i\le4, such that

\displaystyle\int_{-1}^1f(t)\,\mathrm dt\approx c_1f(x_1)+\cdots+c_4f(x_4)

You can either try solving for each with the help of a calculator, or look up the values of the weights and nodes (they're extensively tabulated, and I'll include a link to one such reference).

Using the quadrature, we then have

\displaystyle\int_{-1}^1f(t)\,\mathrm dt\approx0.3749f(-0.8611)+0.6521f(-0.3400)+0.6521f(0.3400)+0.3749f-0.8611)
\displaystyle\int_{-1}^1f(t)\,\mathrm dt\approx0.5790
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3 years ago
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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