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blondinia [14]
3 years ago
6

What is the total r value for a wall made of 4 inches of wood, 2 inches of fiberglass, and 3 inches of foam? assume that the r v

alues for a 1-inch thickness of these materials is given by: r(1" wood) = 2, r(1" fiberglass) = 4, and r(1" foam) = 5?
Mathematics
1 answer:
Vladimir [108]3 years ago
8 0
The total R value is computed from the R-values of the components in the stack as ...
  (inches of wood)*(R-value of wood) +(inches of fiberglass)*(R-value of fiberglass) +(inches of foam)*(R-value of foam)
  = (4 in)(2 /in) +(2 in)(4 /in) +(3 in)(5 /in)
  = 8 +8 +15
  = 31

The total R-value of the wall is 31.
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RideAnS [48]

The question is related to integration and we have to used the following formula

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6 0
3 years ago
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Svet_ta [14]
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4 0
3 years ago
8(3n + 5) = -32<br> what does n =
olga_2 [115]

Answer: n = -3

Step-by-step explanation:

8(3n + 5) = -32

  • <em>Divide both sides by 8.</em>

(3n + 5) = -4

  • <em>Subtract 5 by both sides.</em>

3n = -4 - 5

3n = -9

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8 0
3 years ago
5 students participated in a push-up competition.
Wittaler [7]

Answer: 9

Step-by-step explanation:

Formula : Mean = \dfrac{\text{Sum of observations}}{\text{Number of observaions}}

Given: 5 students participated in a push-up competition.

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Mean = \dfrac{12+7+10+77+5}{5}

=\dfrac{45}{5}=9

Hence, the mean number of push-ups = 9

4 0
2 years ago
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