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blondinia [14]
3 years ago
6

What is the total r value for a wall made of 4 inches of wood, 2 inches of fiberglass, and 3 inches of foam? assume that the r v

alues for a 1-inch thickness of these materials is given by: r(1" wood) = 2, r(1" fiberglass) = 4, and r(1" foam) = 5?
Mathematics
1 answer:
Vladimir [108]3 years ago
8 0
The total R value is computed from the R-values of the components in the stack as ...
  (inches of wood)*(R-value of wood) +(inches of fiberglass)*(R-value of fiberglass) +(inches of foam)*(R-value of foam)
  = (4 in)(2 /in) +(2 in)(4 /in) +(3 in)(5 /in)
  = 8 +8 +15
  = 31

The total R-value of the wall is 31.
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\sqrt{x  \: }  = 8 \\ x = 8 {}^{2} \\ x = 64

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A lady bought plates and bowls, 24 items in all. The price of each bowl was 60 cents; the price of each plate was 75 cents. The
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.60          .75          1.35
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answer: 4
 
6 0
3 years ago
A newborn child receives a $20,000 gift toward college education from her grandparents. How much will the 20,000 be worth in 17
Alexus [3.1K]

Answer:

The amount the $20.000 will be worth in 17  years at compound interest is $65068.443

Step-by-step explanation:

Here we have the Principal, P = $20,000.00

The annual interest rate, r = 7% = 0.07

Time , t = 17 years

Number of compounding period per year, m = quarterly = 4

The compound interest can be found from the following formula;

Amount, \ A = P \left (1 + \frac{1}{r}  \right )^{mt}

Therefore, by plugging the values of the equation parameters, we have;

Amount, \ A = 20000 \left (1 + \frac{0.07}{4}  \right )^{4 \times 17} = \$  65068.443

Therefore, the amount the $20.000 will be worth in 17  years at compound interest = $65068.443.

7 0
3 years ago
Find the limit of the function by using direct substitution.
serg [7]

Answer:

Option a.

\lim_{x \to \frac{\pi}{2}}(3e)^{xcosx}=1

Step-by-step explanation:

You have the following limit:

\lim_{x \to \frac{\pi}{2}{(3e)^{xcosx}

The method of direct substitution consists of substituting the value of \frac{\pi}{2} in the function and simplifying the expression obtained.

We then use this method to solve the limit by doing x=\frac{\pi}{2}

Therefore:

\lim_{x \to \frac{\pi}{2}}{(3e)^{xcosx} = \lim_{x\to \frac{\pi}{2}}{(3e)^{\frac{\pi}{2}cos(\frac{\pi}{2})}

cos(\frac{\pi}{2})=0\\

By definition, any number raised to exponent 0 is equal to 1

So

\lim_{x\to \frac{\pi}{2}}{(3e)^{\frac{\pi}{2}cos(\frac{\pi}{2})} = \lim_{x\to \frac{\pi}{2}}{(3e)^{\frac{\pi}{2}(0)}\\\\

\lim_{x\to \frac{\pi}{2}}{(3e)^{0}} = 1

Finally

\lim_{x \to \frac{\pi}{2}}(3e)^{xcosx}=1

6 0
3 years ago
I need help!! thnaks
liraira [26]

Answer:

7a + 2b

Step-by-step explanation:

Given

4a + 3b + 3a - b ← collect like terms

4a + 3a + 3b - b

= 7a + 2b

3 0
3 years ago
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