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Tems11 [23]
3 years ago
12

If a translation maps ∠D onto ∠B, which of the following statements is true? triangle CAB, point E is on segment AC between poin

ts A and C and point D is on segment BC between points B and C, creating segment ED ΔCED ~ ΔCAB ΔCED ~ ΔCBA segment CD ≅ 2 segment CA segment CD ≅ 2 segment CB
Mathematics
1 answer:
mrs_skeptik [129]3 years ago
4 0

Answer:

The correct option is;

ΔCED ~ ΔCAB

Step-by-step explanation:

Given that the translation maps angle ∠D to angle ∠B, we have;

Angle ∠D is congruent to ∠B (Given)

Segment ED is parallel to segment AB (lines having similar angles to a common transversal)

Therefore, ∠A is congruent to ∠E, (Angle on the same side of a transversal to two parallel lines)

∠C is congruent to ∠C reflexive property

Therefore, we have;

∠C ≅ ∠C

∠E ≅ ∠A  

∠D ≅ ∠B

Which gives ΔCED is similar to ΔCAB (not ΔCBA)

You might be interested in
How many solution does this have and how do you solve it
Vadim26 [7]

Answer:

Infinite solutions

Step-by-step explanation:

To determine the number of solutions a system has, you need its slope. If the slopes are the same, check if the equations are equivalent or not.

To find the slope, rearrange the equation to isolate "y", which makes it slope-intercept form y = mx + b.

"x" and "y" represent points on the line.

"m" represents the slope, which is how steep a line is.

"b" represents the y-intercept (where the graph hits the y-axis).

Isolate "y" in both equations:

x + 3y = 0

3y = -x        Subtract 'x' from both sides

y = -x/3        Divide both sides by 3.

y = -\frac{1}{3}x

The slope is -1/3.

9y = -3x

y = -3x/9        Divide both sides by 9

y = -\frac{3}{9}x        Reduce the fraction to lowest terms

y = -\frac{1}{3}x

The slope is -1/3, but the two equations are the same.

Since the equations are the same, or <u>equivalent</u>, the two lines are always touching. The solution of a system means where two lines intersect, or meet. Therefore, <u>there are infinite solutions</u>.

5 0
3 years ago
Find the equation that Passes through the point (2,3) and is parallel to the line y=5x-9. First find the equation of the line in
KATRIN_1 [288]
Since It's parallel to <span>y=5x-9 the slope of this new line is 5
so the equation looks like </span><span>y=5x+b
to find be we just replace x by 2 and y by 3
3=10-b so b = -7
the equation is </span><span>y=5x-7</span>
7 0
3 years ago
How do you complete the square to rewrite y= x^ -6x + 15 in vertex form
Vaselesa [24]
Vertex form of a quadratic equation is y=a(x-h)^{2}+k
where (h, k) is the vertex. 

Our aim is to write the expression y=x^{2} -6x+15 in the form 
y=a(x-h)^{2}+k



y=x^{2} -6x+15

y=x^{2} -2*3*x+15

y=(x^{2} -2*3*x+ 3^{2})-3^{2}+ 15

y=(x-3)^{2}-9+15

y=(x-3)^{2}+6
5 0
3 years ago
Its length is
melamori03 [73]

Answer:

$100

Step-by-step explanation:

40x30=1200

1200/12=100

7 0
3 years ago
GRAHAM CORPORATION
astra-53 [7]

Answer:

<h2>Net proceed= s-0.98nd-11</h2>

Step-by-step explanation:

Given that the shares cost $d

n shares will be =$dn

paid 2% commission to her broker= (2/100)*nd= 0.02nd

sold the share for $s

paid a fee of $11

Her net proceeds algebraically will be

Net proceed= s-nd-11-0.02nd

collect like terms

Net proceed= s-(nd-0.02nd)-11

Net proceed= s-0.98nd-11

5 0
3 years ago
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