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pshichka [43]
4 years ago
10

10x-6y=-48 standard to slope intercept form

Mathematics
1 answer:
Anarel [89]4 years ago
5 0

Answer:

y=\frac{5}{3}x+8

Step-by-step explanation:

Remember, slope intercept form is:

y = mx + b

where m is the slope and b is the y-intercept.

To get the given equation into slope-intercept form, we would have to first solve for y in terms of x.

10x - 6y = -48

Subtract 10x from both sides.

-6y = -48 - 10x

Multiply both sides by -1.

6y = 10x + 48

Divide both sides by 6.

y=\frac{5}{3}x+8

And now, looking at the equation that we found and the equation for slope-intercept form, we can see that we have found the equation for 10x - 6y = -48 in slope-intercept form.

I hope you find my answer to be helpful. Happy studying.

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The persons speed is 7 miles per hour.

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A shark descended 23.7 feet to catch a fish. The shark is now at − 65.50 feet. What was his starting point?
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3 years ago
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A man starts walking north at 2 ft/s from a point P. Five minutes later a woman starts walking south at 3 ft/s from a point 500
Vedmedyk [2.9K]

Answer:

The rate at which both of them are moving apart is 4.9761 ft/sec.

Step-by-step explanation:

Given:

Rate at which the woman is walking,\frac{d(w)}{dt} = 3 ft/sec

Rate at which the man is walking,\frac{d(m)}{dt} = 2 ft/sec

Collective rate of both, \frac{d(m+w)}{dt} = 5 ft/sec

Woman starts walking after 5 mins so we have to consider total time traveled by man as (5+15) min  = 20 min

Now,

Distance traveled by man and woman are m and w ft respectively.

⇒ m=2\ ft/sec=2\times \frac{60}{min} \times 20\ min =2400\ ft

⇒ w=3\ ft/sec = 3\times \frac{60}{min} \times 15\ min =2700\  ft

As we see in the diagram (attachment) that it forms a right angled triangle and we have to calculate \frac{dh}{dt} .

Lets calculate h.

Applying Pythagoras formula.

⇒ h^2=(m+w)^2+500^2  

⇒ h=\sqrt{(2400+2700)^2+500^2} = 5124.45

Now differentiating the Pythagoras formula we can calculate the rate at which both of them are moving apart.

Differentiating with respect to time.

⇒ h^2=(m+w)^2+500^2

⇒ 2h\frac{d(h)}{dt}=2(m+w)\frac{d(m+w)}{dt}  + \frac{d(500)}{dt}

⇒ \frac{d(h)}{dt} =\frac{2(m+w)\frac{d(m+w)}{dt} }{2h}                         ...as \frac{d(500)}{dt}= 0

⇒ Plugging the values.

⇒ \frac{d(h)}{dt} =\frac{2(2400+2700)(5)}{2\times 5124.45}                       ...as \frac{d(m+w)}{dt} = 5 ft/sec

⇒ \frac{d(h)}{dt} =4.9761  ft/sec

So the rate from which man and woman moving apart is 4.9761 ft/sec.

3 0
4 years ago
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