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3 years ago

Which speed is the fastest?

1 answer:

5 0

Fastest: 32/3 yards in 15 minutes

18 ft/20 min = .9 ft/min
90 ft/2.5 hrs = 90 ft/150 min = .6 ft/min
20 yd/1.5 hr = 60 ft/90 min = .667 ft/min
32/3 yd/15 min = 32 ft/15 min = 2.133 ft/min

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For f(x) = 5x +1 , find f(-4)

julia-pushkina [17]

For f(x) = 5x +1 , find f(-4)
f(-4) = 5(-4) +1 = -19

answer
A, -19

3 0

3 years ago

D is reflection over y axis

densk [106]

Since it is flipping vertically, it is going OVER the x-axis which is the axis that runs horizontally.

8 0

3 years ago

Read 2 more answers

Jamal wrote the inequality x/16 <6 . Which situation best represented by this inequality Helpppppp

Wittaler [7]

Given problem;

Inequality equation;

$\frac{x}{16}$ < 6

Before we solve, let us first translate this problem.

It simply states that for what value(s) of x will the expression be less than 6.

To find this value, we can simply carry out the normal mathematical simplification.

Simply multiply both sides by 16 to reduce the fraction;

16 x ( $\frac{x}{16}$ ) < 6 x 16

On the left hand side, 16 will cancel out;

x < 96

Any value for which x is less than 96 will make the solution of this problem less than 6.

For example, 95;

$\frac{95}{16}$ = 5.93

This value is less than 6

4 0

3 years ago

Edit: I figured it out, it's 14+7(sqrt sign) 2

Anettt [7]

Answer:

$Perimeter = 14 + 7\sqrt{2}$

Step-by-step explanation:

Given:

Area of the square = 49 in²

Required

Determine the perimeter of the one of the congruent triangles

First, we'll determine the length of the square;

$Area = Length * Length$

Substitute 49 for Area

$49 = Length * Length$

$49 = Length^2$

Take Square root of both sides

$7 = Length$

$Length = 7$

When the square is divided into two equal triangles through the diameter;

2 sides of the square remains and the diagonal of the square forms the hypotenuse of the triangle;

Calculating the diagonal, we have;

$Hypotenuse^2 = Length^2 + Length^2$ -- Pythagoras Theorem

$Hypotenuse^2 = 7^2 + 7^2$

$Hypotenuse^2 = 2(7^2)$

Take square root of both sides

$Hypotenuse = \sqrt{2} * \sqrt{7^2}$

$Hypotenuse = \sqrt{2} * 7$

$Hypotenuse = 7\sqrt{2}$

The perimeter of one of the triangles is the sum of the 2 Lengths and the Hypotenuse

$Perimeter = Length + Length + Hypotenuse$

$Perimeter = 7 + 7 + 7\sqrt{2}$

$Perimeter = 14 + 7\sqrt{2}$

7 0

4 years ago

3. Solve for x. 3r +11 9x - 14 Plss

Studentka2010 [4]

Answer:

x=12

Step-by-step explanation:

use midpoint theorem that said that the small line segment (3x+11) is half of the segment ( 9x -14)

2(3x +11) = 9x -14

6x +22 = 9x -14; distribute

6x -9x = -22-14; subtract 9x and 22 from both sides

-3x = -36; divide both sides by -3

x= 12

4 0

3 years ago