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DaniilM [7]
3 years ago
6

How many grams of dry NH4Cl need to be added to 2.10L of a 0.700M solution of ammonia, NH3, to prepare a buffer solution that ha

s a pH of 8.59? Kb for ammonia is 1.8×10−5.
Chemistry
1 answer:
dezoksy [38]3 years ago
4 0
I got 9.25527 for the pKa 
<span>then for the Henderson-Hasselbalch equation: </span>
<span>9.00=9.25527+log(.600/acid) </span>
10^(-.25527)=(.600/acid)correct to this line. Then 
0.5556 = 0.6/acid and 
acid = 0.6/0.5556 = 1.08 which is the reciprocal of your number) 

<span>.5556/.600M=acid </span>
<span>acid=.925925...M </span>
<span>(.925925)*2.10L= Molarity</span>
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\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

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