1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
algol13
4 years ago
8

12÷2×8 value 120 where would the parentheses go

Mathematics
1 answer:
denis23 [38]4 years ago
7 0

Answer:

(12÷2)×8

Step-by-step explanation:

You might be interested in
Spongebob ordered $965.00 worth of Crabbie Patties. He had to pay tax which was 6%. How much did he need to pay in all?
Kisachek [45]

Answer:

965.06

Step-by-step explanation:

6 0
3 years ago
What is the volume of this solid?
Anettt [7]

Answer:

B- 1,527

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
find the equation of a line which passes through a point (-2,3) and makes an angle of 45° with positive x axis​
xeze [42]

Answer:

3०3333333333333333

43

4 0
3 years ago
The average national SAT score is 1119. If we assume a bell-shaped distribution and a standard deviation equal to 206, what perc
wel

Solution: We are given:

\mu=1119, \sigma =206

a. what percentage of scores will fall between 501 and 1737?

In order to find the percentage of scores that fall between 501 and 1737, we use the z score formula first:

When x = 501, we have:

z=\frac{x-\mu}{\sigma}

        =\frac{501-1119}{206}=-3

When x = 1737, we have:

z=\frac{x-\mu}{\sigma}

        =\frac{1737-1119}{206}=3

Therefore, we have to find P(-3\leq z \leq 3).

From the empirical rule of normal distribution 99.7% of data falls within 3 standard deviation's from mean.

Therefore, 99.7% of scores will fall between 501 and 1737.

b. what percentage of scores will fall between 707 and 1531?

In order to find the percentage of scores that fall between 707 and 1531, we use the z score formula first:

When x = 707, we have:

z=\frac{x-\mu}{\sigma}

        =\frac{707-1119}{206}=-2

When x = 1531, we have:

z=\frac{x-\mu}{\sigma}

        =\frac{1531-1119}{206}=2

Therefore, we have to find P(-2\leq z \leq 2).

From the empirical rule of normal distribution 95% of data falls within 2 standard deviation's from mean.

Therefore, 95% of scores will fall between 707 and 1531.

c. what percentage of scores will fall between 931 and 1325?

In order to find the percentage of scores that fall between 931 and 1325, we use the z score formula first:

When x = 931, we have:

z=\frac{x-\mu}{\sigma}

        =\frac{931-1119}{206}=-1

When x = 1325, we have:

z=\frac{x-\mu}{\sigma}

        =\frac{1325-1119}{206}=1

Therefore, we have to find P(-1\leq z \leq 1).

From the empirical rule of normal distribution 68% of data falls within 1 standard deviation's from mean.

Therefore, 95% of scores will fall between 707 and 1531.


3 0
3 years ago
How far away is the point 12,5 from the origin
Gwar [14]

Answer:

13 units

Step-by-step explanation:

can you please make mine the brainliest thank you :)

7 0
4 years ago
Read 2 more answers
Other questions:
  • What is 52.54 percent of 142 million
    13·2 answers
  • For the piecewise function, find the specified function value
    11·1 answer
  • Can someone help me with this problem please?
    9·1 answer
  • For an imaginary economy, the value of the consumer price index was 140 in 2013, and the inflation rate was 5.0 percent between
    5·1 answer
  • Given the following table, what is the average rate of change from 2 ≤ x ≤ 5 ?
    10·1 answer
  • A comic book collector buys a comic book for $120 and sells it for $250. Find the percent change. type your answer...​
    12·2 answers
  • I need help please !!
    11·1 answer
  • Expand the following quadratic to standard form. <br> y=(x-2)^2+6
    7·1 answer
  • Please help (algebra 1 question)
    13·1 answer
  • A pole that is 3.1 m tall casts a shadow that is 1.16 m long. At the same time, a nearby building casts a shadow that is 46.25 m
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!