Answer:
C x=6
Step-by-step explanation:
sqrt(x+3) = x-3
Square each side
(sqrt(x+3))^2 = (x-3)^2
x+3 = (x-3)^2
x+3 = (x-3)(x-3)
FOIL
x+3 = x^2 -3x-3x+9
Combine like terms
x+3 = x^2 -6x+9
Subtract x from each side
x-x+3 = x^2 -6x-x +9
3 = x^2 -7x +9
Subtract 3 from each side
3-3 = x^2 -7x +9-3
0 = x^2 -7x+6
Factor
0 = (x-6)(x-1)
Using the zero product property
x-6=0 x-1 =0
x=6 x=1
Since we squared we need to check for extraneous solutions
x=1
sqrt(1+3) = 1-3
sqrt(4) = -2
2=-2
False
Extraneous
x=6
sqrt(6+3) = 6-3
sqrt(9) = 3
3=3
True solutions
Okay so i may be wrong but i think that the new coordinates would be (7,5). I’m assuming that the translation is up 2 and 4 to the right so you just follow the rules for translations. (a) being the amount of spaces you’re moving for x and (b) being the amount of spaces you’re moving for y
Translation a units to the right (x,y) ➡️ (x+a, y)
Translation a units to the left (x,y) ➡️ (x-a,y)
Translation b units up (x,y) ➡️ (x,y+b)
Translation b units down (x,y) ➡️ (x,y-b)
i’m not the smartest person ever but hopefully this helps. good luck!!
We are given that the angle a is the right angle. So let
us work from this.
ab = 12 (the vertical side of the triangle)
bc = 13 (which if drawn can be clearly observed to be the
hypotenuse) = the side opposite to angle a
ca = 5 (the horizontal side of the triangle)
Since we are to find for the cosine ratio of angle c or
angle θ, therefore:
cos θ = adjacent side / hypotenuse
cos θ = ca / bc
cos θ = 5 / 13
Check out the attached image below for the illustration
of the triangle.
Try the app math lens it will help you
