Simplify 4^5/4^3 and show steps

Solve for x: 2(3x - 9) = 18x x = -3/2 x = 3/2 x = 0 x = 6

Mila [183]

Remember yo can do anything to an equation as long as you do it to both sides

so
remember distributive property
a(b+c)=ab+ac

so first distribute
2(3x)+2(-9)=18x
6x-18=18x
minus 6x both sides
-18=12x
divide both sides by 12
-18/12=x
-9/6=x
-3/2=x

easier way is to first divide both sides by 2

x=-3/2

5 0

3 years ago

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(3x-2)(3x-2) solve the problem using factoring

Effectus [21]

9x squared - 6x - 6x + 4
9x squared - 12x + 4

5 0

2 years ago

An experiment consists of rolling two fair dice and adding the dots on the two sides facing up. What is the probability that the

notka56 [123]

C. 1/12
The answer should be C. 1/12.

4 0

2 years ago

A leaky faucet has a drip that produces 1.2 drops per second. How many drops will occur in one day?. Show all steps neatly.Write

NemiM [27]

28.8 drops will occur in one day because if you multiply 1.2 by 24, it will equal 24. I multiplied by 24 because 1 day is 24 hours

hope it helped :3

3 0

2 years ago

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Several years ago, 38% of parents who had children in grades K-12 were satisfied with the quality of education the students r

Colt1911 [192]

Answer:

$0.428 - 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.3995$

$0.428 + 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.4564$

We are confident that the true proportion of people satisfied with the quality of education the students receive is between (0.3995, 0.4564), since the lower value for this confidence level is higher than 0.38 we have enough evidence to conclude that the parents' attitudes toward the quality of education have changed.

Step-by-step explanation:

For this case we are interesting in the parameter of the true proportion of people satisfied with the quality of education the students receive

The confidence level is given 95%, the significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical values are:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The estimated proportion of people satisfied with the quality of education the students receive is given by:

$\hat p =\frac{499}{1165}= 0.428$

The confidence interval for the proportion if interest is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

And replacing the info given we got:

$0.428 - 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.3995$

$0.428 + 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.4564$

We are confident that the true proportion of people satisfied with the quality of education the students receive is between (0.3995, 0.4564), since the lower value for this confidence level is higher than 0.38 we have enough evidence to conclude that the parents' attitudes toward the quality of education have changed.

8 0

3 years ago