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3 years ago

What is the answer to3k-8+2k

Mathematics

2 answers:

Sati [7]3 years ago

5 0

$3k-8+2k$

$(3k+2k)-8$

$5k-8$

miv72 [106K]3 years ago

3 0

Do this: 3k - 8 + 2k

Then: k - 8 = 0 (Subtract the K's from both sides)

Finally: k = 8 (Add the 8 from both sides)

Your answer would be "k = 8"

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Use the Venn diagram to list the set of elements of A ∩ B in roster form.

artcher [175]

Answer:

A. {e, h}

Step-by-step explanation:

In a Venn diagram, the set of elements in any intersection can simply be visualised. The elements contained in the region where the circles representing different sets overlap, are the set of elements of intersection.

In the Venn diagram given, the set of elements contained in the region where the circles representing A and B overlap are {e, h}.

{e, h} is common to both set A and set B.

7 0

3 years ago

The price of a cycle is reduced by 25 per cent. The new price is reduced by a further 20 per cent. The two reductions together a

alexandr402 [8]

$100\%-25\%=75\%=\frac{75}{100}=0.75\\\\100\%+20\%=120\%=\frac{120}{100}=1.2\\\\1.2\cdot0.75=0.9=0.9\cdot100\%=90\%\\\\100\%-90\%=10\%\\\\Answer:Single\ reduction\ is\ 10\%.$

6 0

3 years ago

8 grams = milligrams

Digiron [165]

Answer:

8,000 miligrams

Step-by-step explanation:

There's 1000 milligrams in a gram so you would have to do multiplication.

which if you do..

8x1000

you should get...

8000 milligrams

4 0

3 years ago

Read 2 more answers

Make q the subject of the formula 2(q+p)=1+5q

Semenov [28]

Answer:

Step-by-step explanation:

2q + 2p = 1 + 5q

-3q + 2p = 1

-3q = 1 - 2p

3q = 2p - 1

q = (2p -1)/3

3 0

3 years ago

Given circle X with radius 10 units and chord AB with length 12 units, what is the length of segment CX, which bisects the chord

andrew-mc [135]

Consider the circle with center X, as shown in the figure.

Draw the diameter of the circle which is parallel to cherd AB, as shown in the figure.

Since the diameter and AB are parallel, then the line segment XC which bisects AB at C, will be perpendicular to AB.

SO triangle XCB is a right triangle. Thus the length of CX, by the Pythagorean theorem is

$\sqrt{ XB^{2}- CB^{2}} = \sqrt{ 10^{2}- CB^{6}}= \sqrt{100-36}= \sqrt{64}=8$ units.

Answer: 8 units

7 0

3 years ago