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4 years ago

Carly has 536 marbles. Kim has 497 marbles how many marbles does carly need to give

Mathematics

1 answer:

xxTIMURxx [149]4 years ago

8 0

Answer:

Step-by-step explanation:

get 536 and grab numbers to subract from it for example 536-10 or anything like that to help u find out or add to 497 to get to 536 to see what u have to subtract from 539

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Animal populations are not capable of unrestricted growth because of limited habitat and food supplies. Under such conditions th

trasher [3.6K]

Answer:

(a) 100 fishes

(b) t = 10: 483 fishes

t = 20: 999 fishes

t = 30: 1168 fishes

(c)

$P(\infty) = 1200$

Step-by-step explanation:

Given

$P(t) =\frac{d}{1+ke^-{ct}}$

$d = 1200\\k = 11\\c=0.2$

Solving (a): Fishes at t = 0

This gives:

$P(0) =\frac{1200}{1+11*e^-{0.2*0}}$

$P(0) =\frac{1200}{1+11*e^-{0}}$

$P(0) =\frac{1200}{1+11*1}$

$P(0) =\frac{1200}{1+11}$

$P(0) =\frac{1200}{12}$

$P(0) = 100$

Solving (a): Fishes at t = 10, 20, 30

$t = 10$

$P(10) =\frac{1200}{1+11*e^-{0.2*10}} =\frac{1200}{1+11*e^-{2}}\\\\P(10) =\frac{1200}{1+11*0.135}=\frac{1200}{2.485}\\\\P(10) =483$

$t = 20$

$P(20) =\frac{1200}{1+11*e^-{0.2*20}} =\frac{1200}{1+11*e^-{4}}\\\\P(20) =\frac{1200}{1+11*0.0183}=\frac{1200}{1.2013}\\\\P(20) =999$

$t = 30$

$P(30) =\frac{1200}{1+11*e^-{0.2*30}} =\frac{1200}{1+11*e^-{6}}\\\\P(30) =\frac{1200}{1+11*0.00247}=\frac{1200}{1.0273}\\\\P(30) =1168$

Solving (c): $\lim_{t \to \infty} P(t)$

In (b) above.

Notice that as t increases from 10 to 20 to 30, the values of $e^{-ct}$ decreases

This implies that:

${t \to \infty} = {e^{-ct} \to 0}$

So:

The value of P(t) for large values is:

$P(\infty) = \frac{1200}{1 + 11 * 0}$

$P(\infty) = \frac{1200}{1 + 0}$

$P(\infty) = \frac{1200}{1}$

$P(\infty) = 1200$

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3 years ago

The sum of 8 and joses score is 35 use the variable j yo represent josés score

OLEGan [10]

Answer:

8 + j = 35

subtract 8 from both sides

j = 27

Step-by-step explanation:

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3 years ago

If f(x) = -3x + 4 and g(x) = 2, solve for the value of x for which f(x) = g(x) is true.

agasfer [191]

Answer:

-2

Step-by-step explanation:

-3(2)+4

-6+4

-2

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3 years ago

The coordinates of Trapezoid EFGH are E(8, 8), F(8,10), G(1, 6), and H(4, 1). The image of EFGH under dilation is E’F’G’H’.

Sergeu [11.5K]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

Below are the choices:

A) (2, 6)
B) (4, 6) 
C) (2, 5) 
D) (4, 5)

The answer should be: (4, 5)
E = (8, 8) -----> E' = (4, 4) = (8/2, 8/2)
F = (8, 10) -----> F' = (8/2, 10/2) = (4, 5)

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3 years ago

8x-6y=54 in slope intercept form please!!

NikAS [45]

Answer: y= 4/3x-9

Step-by-step explanation:

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3 years ago