Given:
The equation
goes through the coordinates (6,5) and (-2,-5).
To find:
The values of A and B.
Solution:
We have,

It goes through the coordinates (6,5) and (-2,-5). It means these points will satisfy the equation.

...(i)

...(ii)
Adding (i) and (ii), we get


Divide both sides by 4.

Put A=5 in (i), we get
Divide both sides by 5.

Therefore, the values of A and B are 5 and -4 respectively.
Let the width = x
=>length = 2x-1
91= x(2x-1)=2x^2-x
2x^2-x-91=0
=(2x+13)(x-7)
=> x=-13/2=> no
=>x= 7 cm
I'm not going to give you the answer but I'll help you.
Step-by-step explanation:
Start by writing down your thoughts down and then form them into a paragraph.
- Write down your opinion of what classic is
- Give 3 traits/characteristics that makes that thing classic (high-quality, timeless, aged, eternal, original etc.)
- Then write down whether or not you think your definition of classic is different from the googled definition
<h2><u>
If you need more help let me know!</u></h2>








There are two critical points, at which we have


Answer:
son's present age = 30
father's present age=60
Step-by-step explanation:
his son's present age = x years
his father's present age = 2x years
before 20 years his son's age=(x-20) years
before 20 years father's age=(2x-20) years4(x-20)=(2x-20)
4x-80=2x-20
4x-2x=80-20
2x=60
x=30