<h2>
The first term of the given sequence (a) = 6561</h2>
Step-by-step explanation:
Let the first term = a and common difference = d
Given,
= 729 and 
= 243
To find, the first term of the given sequence (a) = ?
We know that,
The nth term of a G.P.
The 3rd term of a G.P.
⇒ 
= 729 ..............(1)
The 4th term of a G.P.
⇒ 
= 243 ..............(2)
Dividing equation (2) by (1), we get
= 
⇒ 
Put in equation (1), we get
= 729
⇒ 
= 729
⇒ a = 9 × 729 = 6561
∴ The first term of the given sequence (a) = 6561
Answer:
10 is answer of this question
Answer:
1/9
Step-by-step explanation:
You can put in any 2 numbers that would make a-b=2 true, so if you use a=4 and b=2, then 3^2/3^4=1/9. This is still true with any 2 numbers that make a-b=2 true. Hope this helps!
We are given the inequality. Solving it,
4x/9 - 10 > x/3 - 12
4x/9 - x/3 > -12 + 10
x/9 > -2
x > -18
The graph of the solution would composed of all values greater than -18<span />
