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CaHeK987 [17]
4 years ago
15

Without changing their values, convert the following 2's complement binary numbers into 8-bit 2's complement numbers. (12 points

) a. 1010 b. 011001 c. 1111111000
Mathematics
1 answer:
Alexxandr [17]4 years ago
3 0

Answer:

a) 8-bit representation = 11111010

b) 8-bit representation = 00011001

c) 8-bit representation = 11111000

Step-by-step explanation:

a. 1010

4-bit 2's complement binary representation

decimal value = -6

Since the number is negative pad with 1 to the left of MSB  

8-bit representation = 11111010

b. 011001

6-bit 2's complement binary representation

decimal value = 25

Since the number is positive pad with 0 to the left of MSB  

8-bit representation = 00011001

c. 1111111000

10-bit 2's complement binary representation

decimal = -8

Since the number is negative discard left most two bits  

8-bit representation = 11111000

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Answer:

x = 1 / 3

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Step-by-step explanation:

First move everything onto one side.

6x^2 + 7x - 3 = 0

Divide by 6:

x^2 + 7/6x - 0.5 = 0

Now, you can move the 0.5 to the other side because it is determined that this is not factorable.

x^2 + 7/6x = 0.5

Now you have to complete the square.

Take 1 / 2 of 7 / 6 and square it.

49 / 144

x^2 + 7/6x + 49/144 = 0.5 + 49/144

(x + 7 / 12)^2 = 121 / 144

Square root:

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Find the real numbers x and y.<br> 27+yi= 11-x + 4i
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\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \:x = -16

\qquad \tt \rightarrow \: y =4

____________________________________

\large \tt Solution  \: :

\qquad \tt \rightarrow \: 27 + yi = 11 - x + 4i

\qquad \tt \rightarrow \: yi + x = 11 + 4i - 27

\qquad \tt \rightarrow \: x + yi =  - 16 + 4i

By equating both equations we get :

\qquad \tt \rightarrow \: x =  - 16

\qquad \tt \rightarrow \: y = 4

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Answer:

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Step-by-step explanation:

<u>Seven less than the product of a number n and 1/6 is no more than 94, translating:</u>

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<u>Solving for n:</u>

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