Part A: Solve for A

I NEED HELP WITH THIS NOW

docker41 [41]

Answer:480

Step-by step

8 0

3 years ago

Read 2 more answers

Order phenobarbital 30 mg. available: phenobarbital gr 1/4. dose to be given: _____

iVinArrow [24]

$30\,mg\times\dfrac{1\,gr}{64.79891\,mg}\times\dfrac{1\,tab}{\frac{1}{4}\,gr}=\dfrac{30\cdot 4}{64.79891}\,tab\approx1.852\,tab$

The dose to be given is about 1.85 of the 1/4 grain tablets.

5 0

3 years ago

Let f(x)=x^2-4x+1. write f(x) in standard form

34kurt

$y = x^2 - 4x + 1$

The method to change it to the form $y = a(x-h)^2+k$ is to complete the square.
$y=x^2-4x+1 \\ 
y-1 = x^2-4x \\ y-1+4 = x^2-4x+4 \\ y+3=(x-2)^2 \\ y=(x-2)^2-3$

6 0

3 years ago

Consider the relationship between the number of bids an item on eBay received and the item's selling price. The following is a s

n200080 [17]

Answer:

Let's assume the following data:

Price in Dollars (X) 26 29 32 38 47

Number of Bids (Y) 12 13 15 16 18

For our case we have this:

n=10 $\sum x = 172, \sum y = 74, \sum xy = 2623, \sum x^2 =6194, \sum y^2 =1118$

$r=\frac{5(2623)-(172)(74)}{\sqrt{[5(6194) -(172)^2][5(1118) -(74)^2]}}=0.974$

So then the correlation coefficient would be r =0.974

Step-by-step explanation:

Previous concepts

The correlation coefficient is a "statistical measure that calculates the strength of the relationship between the relative movements of two variables". It's denoted by r and its always between -1 and 1.

Solution to the problem

And in order to calculate the correlation coefficient we can use this formula:

$r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}$

Let's assume the following data

Price in Dollars (X) 26 29 32 38 47

Number of Bids (Y) 12 13 15 16 18

For our case we have this:

n=10 $\sum x = 172, \sum y = 74, \sum xy = 2623, \sum x^2 =6194, \sum y^2 =1118$

$r=\frac{5(2623)-(172)(74)}{\sqrt{[5(6194) -(172)^2][5(1118) -(74)^2]}}=0.974$

So then the correlation coefficient would be r =0.974

5 0

3 years ago

40. In a statistics class of 30 students, there were 13 men and 17 women. Two of the men and three of the women received an A in

Harrizon [31]

Answer:

a) 56.67% probability that the student is a woman

b) 16.67% probability that the student received an A

c) 63.33% probability that the student is a woman or received an A.

d) 83.33% probability that the student did not receive an A.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

We have that:

30 students

13 men

17 women

2 men that got an A and 11 men that did not get an A.

3 women that got an A and 14 women that did not get an A.

a. Find the probability that the student is a woman.

30 students, of which 17 are women.

$P = \frac{17}{30} = 0.5667$

56.67% probability that the student is a woman

b. Find the probability that the student received an A.

30 students, of which 5 received an A

$P = \frac{5}{30} = 0.1667$

16.67% probability that the student received an A

c. Find the probability that the student is a woman or received an A.

30 students, of which 17 are women and 2 are men who received an A. So

$P = \frac{19}{30} = 0.6333$

63.33% probability that the student is a woman or received an A.

d. Find the probability that the student did not receive an A.

30 students, of which 25 did not receive an A.

$P = \frac{25}{30} = 0.8333$

83.33% probability that the student did not receive an A.

7 0

3 years ago

Part A: Solve for A​

Part A: Solve for A