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mihalych1998 [28]
3 years ago
5

Julio tested the point (4, –2) to see whether it is a solution to this system of equations. –3x – 2y = –8, y = 2x – 5 His work i

s shown below.
Mathematics
2 answers:
Vaselesa [24]3 years ago
7 0

The answer is B. No he did not check the point in the second equation.

kolezko [41]3 years ago
6 0

if it is solution point (4, –2) must satisfy both equations
(1) –3x – 2y = –8-->-3*4-2*(-2)=-8
-12+4=-8 then-->-8=-8   ok
(2)  y = 2x – 5
-2=2*4-5=3---------->-2 is not 3

the point  (4, –2) is not solution of the system of equations
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3 is the correct answer

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also 36 /12 = 3


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PLEASE HELP ME<br><br> given m||n, fine the value of x.<br><br> (X+12)° (4x-7)°
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Eva8 [605]
<span>The rate of the express train is 15 mph faster than the freight train.
Let's grasp onto this piece of information. 

The rate at which the freight train goes will be labeled "x" (keep in mind rate is just the speed)

If the freight train has a speed of "x" then the express train which is going 15mph faster than the freight train can be represented as "x + 15mph."

Our result is in HOURS, but our speed is in Miles per Hour (Miles/Hour). Meaning we need to multiply our speeds by some time (t).

Let's set up two equations: 
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They are both the same distance so we can set the two equations equal to each other like this: 

18 hours * x mph = 15 hours * (x mph + 15mph)

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Let's simplify the left side (</span>\frac{miles}{hour}*hour = miles)

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Get all the "x" terms on one side by subtracting 15x on both sides. 

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Simplify

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Divide by 3 on both sides to solve for x. 
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So "x" which we chose was the rate of the freight train is 75mph. 
Adding 15mph to the freight train rate gives you the express trains rate which is 90mph. 

Hope that helped. 
8 0
3 years ago
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