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3 years ago

What is the value of k in the equation k/3 - 5 = 34? 11 1/3 13 102 117

Mathematics

2 answers:

mestny [16]3 years ago

6 0

1. Add 5 to both sides

k/3 = 34 + 5

2. Simplify 34 + 5 to 39

k/3 = 39

3. Multiply both side by 3

k = 39 * 3

4. Simplify 39 * 3 to 117

k = 117

Mamont248 [21]3 years ago

4 0

Answer:

D is the answer on Edgen.

Step-by-step explanation:

I took the test.

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Does 1/7 divided by what equals 14

Paul [167]

2*7=14 7/14=2 do yes

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3 years ago

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zhenek [66]

Answer:

0 ≤y ≤ 60

Step-by-step explanation:

The range is values the y can take

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10 ≤y ≤ 60

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3 years ago

Given: JK tangent, KH=16, HE=12 Find: JK.

Y_Kistochka [10]

Answer: $JK=8$

Step-by-step explanation:

You can observe in the figure that JK is a tangent and KH is a secant and both intersect at the point K. Then, according to the Intersecting secant-tangent Theorem:

$JK^2=KE*KH$

You know that:

$KH=KE+HE$

Then KE is:

$KE=KH-HE$

$KE=16-12$

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$JK^2=4*16\\JK^2=64\\JK=\sqrt{64}\\JK=8$

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3 years ago

Suppose we want to build a rectangular storage container with open top whose volume is $$12 cubic meters. Assume that the cost o

Snezhnost [94]

Answer:265.25

Step-by-step explanation:

Given

Volume of box $=12 m^3$

height is 3 times the width

let height, length and breadth be H, L & B

$H=3\times B$

$V=12=L\times B\times H$

4=B^2\times L[/tex]

$L=\frac{4}{B^2}$

Cost of side walls $ $8/m^2$

Cost of base $ $12/m^2$

Cost of side walls $=(2LH+2BH)\cdot 8$

Cost of base $=12LB$

Total cost $C=16LH+16BH+12LB$

$C=48LB+48B^2+12LB$

$C=\frac{192}{B}+48B^2+\frac{48}{B}$

differentiate C w.r.t B to get minimum cost

$\frac{\mathrm{d} C}{\mathrm{d} B}=-\frac{192}{B^2}+2\times 48 B-\frac{48}{B^2}$

$B^3=\frac{240}{2\times 48}$

$B=1.35 m$

$H=3\times 1.35=4.07 m$

L=2.19 m

C=$ 265.25

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3 years ago

As the earth rotates, it travels a distance of 80 miles in 5 minutes. At this constant rate, which equation best represents y, t

solniwko [45]

Answer:

y=16x

Step-by-step explanation:

So, you are given the equation as if y=total distance the earth travels in x minutes. If you are given that you travel 80 miles in 5 minutes, you can plug these value into the variables they are representing and solve for the constant.

Visual:

y=xk y=miles x=minutes k=constant

Plug in your values and you get:

80=5k

Now, you solve for k by diving 5 on both sides, which leaves you with k=16.

Now you plug your value for k into the original equation, leaving you with y=16x

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3 years ago