Let O be the point of intersection of diagonals.
Consider triangles FOE and EOD:
FO = OD, ∠FOE = ∠EOD and OE is a common side ⇒
triangles FOE and EOD are congruent.
In congruent triangles all corresponding sides and are congruent ⇒
EF = DE = 6
A = (-3)
B = (0.5)
|AB| = |0.5 - (-3)| = |0.5 + 3| = |3.5| = 3.5
Answer:
Look at the image, pls give brainliest!
Step-by-step explanation:
Answer:
123.5 square inches
Step-by-step explanation:
Given: To find the area of a rectangle, you have to multiply base times height.
To find the area of a triangle, you have to do base times height devided by 2.
Finding the area: Let's break up this shape into polygons. At the bottom there is a rectangle. We know that to find the area of the rectangle you have to do base times height. 13in•7in will give you <u>91in</u> square for the rectangle.
Now for the triangle. If you can see, if you break the triangle in half, there are 2 right triangles. Let's look at the right one for now. Since we know that to find the area of a triangle you have to do base times height divided by 2, you do 5in•6.5in=32.5in. 32.5in divided by 2 is <u>16.25in </u>square which is the area of one triangle. You might be wondering why i did 5•6.5, and that's because at the bottom of the rectangle you can see it's 13in, and 13in÷2=6.5in.
We already found the area of the rectangle and one triangle. The other triangle is equal to it so we can just do 16.25+16.25=<u>32.5in</u> square for both of the triangles.
Now we add it all up: 32.5+91=123.5 square inches
