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RoseWind [281]
3 years ago
11

Question 5!!!!!!!!!!!!!!!!

Mathematics
1 answer:
postnew [5]3 years ago
7 0

Answer:

median=59

Step-by-step explanation:

big brains for days

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Plz help me asap plz i need help
a_sh-v [17]

what do you need help on ? LMFA O

7 0
3 years ago
Help!
nignag [31]

1) 8 + 4 = -5 + 7

     12   =    2

        FALSE

2) y = -11x + 4

(0, -7):   -7 = -11(0) + 4   ⇒   -7 = 0 + 4   ⇒   -7 = 4   False

(-1, -7):  -7 = -11(-1) + 4   ⇒   -7 = 11 + 4   ⇒   -7 = 15   False

(1, -7):  -7 = -11(1) + 4   ⇒   -7 = -11 + 4   ⇒   -7 = -7   True

(2, 26): 26 = -11(2) + 4   ⇒   26 = -22 + 4   ⇒   26 = -18   False

Answer: C

3) Input       Output

     0                0

  <u>   1    </u>             3            

    2             <u>    6  </u>

    3                 9

 <u>   4    </u>          <u>  12   </u>

    5                 15

    6              <u>   18  </u>

Rule: input is being added by 1, output is 3 times x

4) c = 65h

5) 2x = -6

   \frac{2x}{2} = \frac{-6}{2}

    x = -3

6) 8j - 5 + j = 67

        9j - 5 = 67   <em>added like terms (8j + j)</em>

       <u>      +5</u>   <u>+5 </u>

        9j      = 72

       \frac{9j}{9} = \frac{72}{9}

        j      = 8

7) y = mx + b

<u>   -b</u>    <u>      -b  </u>

y - b = mx

\frac{y - b}{x} = \frac{mx}{x}

\frac{y - b}{x} = m

5 0
3 years ago
What is triple of 1/2 oranges on a recipe?
Elena-2011 [213]
It is 1 and 1\2 oranges hope this helps!!

4 0
3 years ago
Read 2 more answers
(4.1.4) Let X and Y be Bernoulli random variables. Let Z = X + Y. a. Show that if X and Y cannot both be equal to 1, then Z is a
Fynjy0 [20]

Step-by-step explanation:

Given that,

a)

X ~ Bernoulli (p_x) and Y ~ Bernoulli (y_x)

X + Y = Z

The possible value for Z are Z = 0 when X = 0 and Y = 0

and Z = 1 when X = 0 and Y = 1 or when X = 1 and Y = 0

If X and Y can not be both equal to 1 , then the probability mass function of the random variable Z takes on the value of 0 for any value of Z other than 0 and 1,

Therefore Z is a Bernoulli random variable

b)

If X and Y can not be both equal to  1

then,

p_z = P(X=1 or Y=1)\\

p_z = P(X=1)+P(Y=1)-P(=1 and Y =1)

p_z = P(x=1)+P(Y=1)\\\\p_z=p_x+p_y

c)

If both X = 1 and Y = 1 then Z = 2

The possible values of the random variable Z are 0, 1 and 2.

since a  Bernoulli variable should be take on only values 0 and 1 the random variable Z does not have Bernoulli distribution

7 0
3 years ago
A construction crew is lengthening a road. The crew is adding 6 miles to the road each week. The road originally measured 52 mil
PSYCHO15rus [73]

6x + 52 > 130

Subtract 52 from both sides:

6x > 78

Divide both sides by 6:

X > 78/6

X > 13

7 0
3 years ago
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