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3 years ago

A triangle has side lengths of 12, 15, and x. The value of x must ne greater than what?

Mathematics

1 answer:

Bezzdna [24]3 years ago

7 0

Answer:

3 < x < 27

Step-by-step explanation:

We can't tell what "must ne greater" means, so we'll tell you the limits on the side length and you can choose the one that is relevant.

The third side of a triangle must have a length that lies between the difference and sum of the two lengths you know.

15 -12 = 3

15 +12 = 27

The value of x must be between 3 and 27:

3 < x < 27

If you allow the triangle to have zero area, then x can be 3 or 27. Many authors claim such a "triangle" is not allowed, so don't allow those cases.

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conducted an experiment with orange, purple and blue colored lights to grow spinach. During their experiment, they conducted a c

LiRa [457]

Answer:

There is not enough evidence to reject the null hypothesis.

Their sum is greater than the probability value , the data does not fit the experiment and the null is accepted.

Step-by-step explanation:

There are 3 colors so degrees of freedom = 3-1 = 2

The chi square value = 0.85

The p value for chi square =0.85 for 2 degrees of freedom for the left tailed test to be 0.34623 for 0.1,0.05 and 0.01 significance level.

There is not enough evidence to reject the null hypothesis.

The p value for chi square =0.85 for 2 degrees of freedom for the right tailed test to be 0.65377 for 0.1,0.05 and 0.01 significance level.

There is not enough evidence to reject the null hypothesis.

Their sum is greater than the probability value , the data does not fit the experiment and the null is accepted.

8 0

2 years ago

In a right triangle, Sin (30 + x) º = Cos (3x) º. What is the value of x?

pogonyaev

Answer:

$x=15^\circ$

Step-by-step explanation:

In a right triangle:

$\sin \theta =cos(90^\circ-\theta) $ (Complementary angles)$

Therefore, given:

$Sin (30 + x) \º = Cos (3x) \º\\30+x+3x=90^\circ\\30+4x=90^\circ\\4x=90^\circ-30^\circ\\4x=60^\circ\\$Divide both sides by 4\\x=15^\circ$

5 0

3 years ago

Is the following a function ?

Vanyuwa [196]

Yes it is a function

6 0

3 years ago

Heyy can you please help me posted picture of question

vichka [17]

We can use quadratic formula to determine the roots of the given quadratic equation.

The quadratic formula is:

$x= \frac{-b+- \sqrt{ b^{2} -4ac} }{2a}$

b = coefficient of x term = 4
a = coefficient of squared term = 1
c = constant term = 7

Using the values, we get:

$x= \frac{-4+- \sqrt{16-4(1)(7)} }{2(1)} \\ \\ 
x= \frac{-4+- \sqrt{-12} }{2} \\ \\ 
x= \frac{-4+-2 \sqrt{-3} }{2} \\ \\ 
x= -2+- \sqrt{-3}$

So, the correct answer to this question is option A

7 0

3 years ago

Pls help me and show work pls

ElenaW [278]

3/6 cause there are 3 evens and 3 odds on a dice

3 0

2 years ago