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3 years ago

Given y = 4x + 3, what effect does changing the equation to y = 4x − 3 have on the y-intercept?

Mathematics

1 answer:

Blababa [14]3 years ago

3 0

Answer:

moves down six

Step-by-step explanation:

say x is 1

plug it in and it moves down six

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Help needed please <br> I need to submit it by am hour

Tasya [4]

Answer:663

Step-by-step explanation:

4 0

3 years ago

The Rockwell hardness index for steel is determined by pressing a diamond point into the steel and measuring the depth of penetr

anygoal [31]

Answer:

We conclude that the steel has an average hardness index of at least 64.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 64

Sample mean, $\bar{x}$ = 62

Sample size, n = 50

Alpha, α = 0.051

Sample standard deviation, s = 8

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 64\\H_A: \mu < 64$

We use one-tailed(left) z test to perform this hypothesis.

Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$z_{stat} = \displaystyle\frac{62 - 64}{\frac{8}{\sqrt{50}} } = -1.767$

Now, $z_{critical} \text{ at 0.05 level of significance } = -2.33$

Since,

$z_{stat} > z_{critical}$

We fail to reject the null hypothesis and accept the null hypothesis. Thus, we conclude that the steel has an average hardness index of at least 64.

8 0

3 years ago

PLEASE, I NEED HELP!!!!!!

Rasek [7]

Okay so you're correct answer in this situation would be A but it could alsobe C

3 0

3 years ago

Write the quadratic function with the following transformations: vertical shrink by 3, left 4, down 9.

xz_007 [3.2K]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\$

$\bf \bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind, let's see

so, the parent equation could be
y = x² ====> y = A(x + C)² + D

shrink by 3, A = 3
left 4, C = +4
down 9, D = 9

7 0

3 years ago

Any and all answers will get a 5 star rating

Afina-wow [57]

Sorry about that i didnt read the question properly

3 0

3 years ago

Read 2 more answers