If in a number plate two different alphabets need to be selected then there are 650 such number plates that can be formed in such a way that the alphabets come in increasing order.
Given that a number plate can be formed using 2 alphabets which must come in increasing order.
We are required to find the number of plates that can be formed.
Number of total alphabets=26.
The number of plates will be equal to the number of ways in which two alphabets can be arranged.
Combination is the number of ways in which some combinations can be formed. It is expressed as n
=n!/r!(n-r)!
Number of license plates=26
*25
=26*25
=650 plates
Hence If in a number plate two different alphabets need to be selected then there are 650 such number plates that can be formed in such a way that the alphabets come in increasing order.
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Answer:
This number "four" is the maximum possible number of positive zeroes (that is, all the positive x-intercepts) for the polynomial f (x) = x 5 – x 4 + 3x 3 + 9x 2 – x + 5. Affiliate However, some of the roots may be generated by the Quadratic Formula , and these pairs of roots may be complex and thus not graphable as x -intercepts.
can calculate and graph the roots (x-intercepts), signs, Local Maxima and Minima, Increasing and Decreasing Intervals, Points of Inflection and Concave Up/Down intervals.
Step-by-step explanation:
The racer take 4 hours (between 8:00 to 12:00) to race 3/4 of 6 miles
3/4 of 6 miles = 18/4 = 4.5 miles
4 hours ⇒ 4.5 miles
1 hour ⇒ 4.5 ÷ 4 = 1.125 miles
The time taken to complete 6 miles = 6 ÷ 1.125 = 16/3 hours = 5.3 hours
Answer:
13.92
Step-by-step explanation:
We have that the critical z-score associated with 85% to the left is 1.04, we know that by table.
So we have to:
m + z * (sd) = 16
where m is the mean, z is the critical z-scor and sd is the standard deviation, if we replace we are left with:
m + 1.04 * (2) = 16
m = 16 - 1.04 * (2)
m = 13.92
Therefore, the average weight if 85% of cucumbers weigh less than 16 ounces is 13.92
