You can find the slope and y-intercept, and make an equation in slope- intercept form and them just plug in the other x values in the equation.
Using the intersecting chord theorem:
15 x 2 = 5 x n
Simplify:
30 = 5n
Divide both sides by 5:
n = 30/5
n = 6 m
8 x n+8 = 16 x n+2
Simplify:
8n +64 = 16n +32
Subtract 8n from both sides:
64 = 8n +32
Subtract 32 from both sides:
32 = 8n
Divide both sides by 8:
n = 32 /8
n = 4
Answer:
6:15
Step-by-step explanation:
Hope this helps, lemme know if you need any further help (:
<h2>9.</h2><h3>Given</h3>
<h3>Find</h3>
- linear approximation to the volume when the radius increases 0.4 cm
<h3>Solution</h3>
The equation for volume of a sphere is
... V = (4/3)π·r³
Differentiating gives
... dV = 4π·r²·dr
Filling in the given numbers gives
... change in volume ≈ 4π·(15 cm)²·(0.4 cm)
... = 360π cm³ ≈ 1130.97 cm³ . . . . . . volume of layer 4mm thick
<h2>11.</h2><h3>Given</h3>
- an x by x by 2x cuboid with surface area 129.6 cm²
- rate of change of x is 0.01 cm/s
<h3>Find</h3>
<h3>Solution</h3>
The area is that of two cubes of dimension x joined together. The area of each such cube is 6x², but the two joined faces don't count in the external surface area. Thus the area of the cuboid is 10x².
The volume of the cuboid is that of two cubes joined, so is 2x³. Then the rate of change of volume is
... dV/dt = (d/dt)(2x³) = 6x²·dx/dt
We know x² = A/10, where A is the area of the cuboid, so the rate of change of volume is ...
... dV/dt = (6/10)A·dx/dt = 0.6·(129.6 cm²)(0.01 cm/s)
... dV/dt = 0.7776 cm³/s
Answer:
D) C': ( -3, -2), D': ( -4, 1), E': ( -1, -2)
Step-by-step explanation:
Formula for this equation:
(x - 5, y - 3)
C:
(2, 1)
(x - 5, y - 3)
C': ( -3, -2)
E:
(4, 1)
(x - 5, y - 3)
E': ( -1, -2)
D:
(1, 4)
(x - 5, y - 3)
D': ( -4, 1)
