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REY [17]
3 years ago
15

How would you solve this?

Mathematics
1 answer:
Nady [450]3 years ago
7 0

16c^3d^{14}\cdot3c^7d=(16)(3)(c^3c^7)(d^{14}d)=48c^{3+7}d^{14+1}=48c^{10}d^{15}\\\\2c^5\cdot2d^2\cdot2cd=(2)(2)(2)(c^5c)(d^2d)=8c^{5+1}d^{2+1}=8c^6d^3\\\\\dfrac{16c^3d^{14}\cdot3c^7d}{2c^5\cdot2d^2\cdot2cd}=\dfrac{48c^{10}d^{15}}{8c^6d^3}=\dfrac{48}{8}c^{10-6}d^{15-3}=6c^4d^{12}\\----------------------------------\\\\\dfrac{16c^3d^{14}\cdot3c^7d}{2c^5\cdot2d^2\cdot2cd}+5c^4d^{12}=6c^4d^{12}+5c^4d^{12}=11c^4d^{12}

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